What caused people to accept the geocentric model of the universe?

For the ride to be comfortable, the magnitude of acceleration must not exceed 32 m/s2. What is the fastest constant speed that a

VMariaS [17]

Answer:

the maximum possible constant speed is 8 m/sec

Explanation:

from the image, Given that

r(t) = (2t, t²,t²/3), -5 ≤ t ≤ 5

Given that the curvature K(t) = 2 / ( t² + 2)²

note that t² + 2 ≥ 2

(t² + 2)² ≥ 4

1 / (t² + 2)² ≤ 1/4

2 / (t² + 2)² ≤ 1/2

Also note that k(0) = 1/2

The normal component of acceleration satisfies aN = kv²

where v = ║v(t)║is the speed of the roller coaster.

The maximum possible normal component of acceleration is 32

so, aN ≤ 32 every where on the track

aN = kv² ≤ 1/2v² ≤ 32

v² ≤ 64

Therefore, the maximum possible constant speed is 8 m/sec

7 0

3 years ago

A northbound train and a southbound train meet each other on parallel tracks heading in opposite directions. The northbound trai

SSSSS [86.1K]

Answer:

50mph,60mph

Explanation:

Let speed of southbound train=x mph

Speed of northbound train,y=x+16 mph

Distance between two trains after 1.5 hour,174 miles.

We have to find the speed of two trains.

Distance= $speed\times time$

Using the formula

$174=1.5x+1.5(x+16)$

$174=1.5(x+x+16)$

$174=(2x+16)\times 1.5$

$174=3x+24$

$3x=174-24=150$

$x=\frac{150}{3}=50mph$

$y=x+16=50+16=66mph$

4 0

3 years ago

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HELP!! An illustration of a pendulum at 3 positions of a pendulum. The equilibrium position is labeled B. The other two position

zmey [24]

Answer

the answer is A and c

Explanation:

i got it right on edge

5 0

3 years ago

Read 2 more answers

A mass spectrometer is being used to separate common oxygen-16 from the much rarer oxygen-18, taken from a sample of old glacial

Nataly_w [17]

Answer:

0.092 m

Explanation:

A charged moving particle immersed in a region with magnetic field follows a circular trajectory at constant speed (uniform circular motion), since the magnetic forces acts perpendicular to the direction of motion of the particle.

Since the magnetic force acts as centripetal force, we can write:

$qvB=m\frac{v^2}{r}$

where

q is the charge of the particle

v is its velocity

B is the strength of the magnetic field

m is the mass of the particle

r is the radius of the orbit

Solving the equation for r,

$r=\frac{mv}{qB}$

For the ion of oxygen-16, we have:

$m_A=2.66\cdot 10^{-26}kg$

$q_A = 1.6\cdot 10^{-19}C$ (it is singly charged)

$v_A=2.90\cdot 10^6 m/s$

$B_A=1.30 T$

So the radius of its orbit is

$r_A=\frac{m_A v_A}{q_A B_A}=\frac{(2.66\cdot 10^{-26})(2.90\cdot 10^6)}{(1.6\cdot 10^{-19})(1.30)}=0.371 m$

For the ion of oxygen-18, we have:

$m_B = \frac{18}{16}m_A = 2.99\cdot 10^{-26}kg$

$q_B = 1.6\cdot 10^{-19}C$ (it is singly charged)

$v_B=2.90\cdot 10^6 m/s$

$B_B=1.30 T$

So the radius of its orbit is

$r_B=\frac{m_B v_B}{q_B B_B}=\frac{(2.99\cdot 10^{-26})(2.90\cdot 10^6)}{(1.6\cdot 10^{-19})(1.30)}=0.417 m$

After each ion has travelled a semicircle, the separation between the two ions will be twice the difference in their radius, so:

$d=2(r_B-r_A)=2(0.417-0.371)=0.092 m$

3 0

3 years ago

If a cannonball is fired horizontally it will not go in a straight line why?

goldfiish [28.3K]

Explanation:

A projectile (Cannon ball) is launched at an angle to the horizontal and rises up to a peak while moving horizontally. When it reaches the peak, the projectile starts to fall.

5 0

2 years ago