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2 years ago

1- Which comparison is NOT true?

Mathematics

1 answer:

Irina18 [472]2 years ago

6 0

Answer:

Step-by-step explanation:

Process of Elimination:

A: 3.976 is greater than 3.97

B: 1.025 is lesser than 1.25

C: 9.145 is greater than 9.14

All of the options checked are true, leaving the answer only to be D.

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a caterer received an order to prepare 120 servings of salad for a banquet. Each serving will weigh 4 ounces. so far the caterer

Ugo [173]

To easier digest this question, we can multiply the 120 servings by 4 ounces to make it into a common unit of measurement. This way, we can compare ounces with ounces instead of ounces to servings.
We then have 480 servings, and the poor caterer only has 60 ounces. We can put that into a fraction, 60/480. From here, things get slightly easier. All we have to do is make it into a fraction we can digest, which would be 1/8. We can turn that fraction into a decimal by simply dividing. We have 0.125.
Since we are changing from a decimal into a percent, we have to move the decimal point two places to the right. We have out final answer of 12.5%.

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3 years ago

after a party, you have 2/5 of the brownies you made left over. there are 16 left. how many brownies did you make for the party

vodomira [7]

16 = 2/5
16 ÷ 2 = 2/5 ÷ 2/1
8 = 1/5
8 * 5 = 1/5 * 5
40 = 5/5
You started the party with 40 brownies

7 0

4 years ago

Read 2 more answers

A genetics experiment involves a population of fruit flies consisting of 1 male named Bart and 3 females named Charlene, Diana,

kenny6666 [7]

Answer:

(b) $\frac{1}{2}$

Step-by-step explanation:

1 male named Bart (b)

3 females named Charlene(c), Diana(d), and Erin(e).

Since there is replacement, the possible samples are:

bb, bc, be, bd, cb, cc, cd, ce, db, dc, dd, de, eb, ec, ed, and ee.

Total Number of pairs = 16

Event of picking 2 males:bb

Event of 1 male:bc,cb,bd,db,be,eb

Event of picking 0 males:

cc, cd, ce, dc, dd, de, ec, ed, and ee.

$\begin{equation*} \begin{matrix}Proportion of males & Probability \\0 & 9/16 \\1 & 6/16 \\2 & 1/16 \end{matrix} \end{equation*}$

b. The mean of the sampling distribution

$\mu = (\frac{9}{16} X0 ) +(\frac{6}{16} X 1)+(\frac{1}{16} X 2) = \frac{8}{16} = \frac{1}{2}$

c. No; the proportion of males is $\frac{1}{4}$ while the mean is $\frac{1}{2}$ .

B. No, the sample mean is not equal to the population proportion of males. These values are not always equal, because proportion is an unbiased estimator.

7 0

3 years ago

We test for a hypothesized difference between two population means: H0: μ1 = μ2. The population standard deviations are unknown

Lina20 [59]

Answer:

The degrees of freedom associated with the critical value is 25.

Step-by-step explanation:

The number of values in the final calculation of a statistic that are free to vary is referred to as the degrees of freedom. That is, it is the number of independent ways by which a dynamic system can move, without disrupting any constraint imposed on it.

The degrees of freedom for the t-distribution is obtained by substituting the values of n1 and n2 in the degrees of freedom formula.

Degrees of freedom, df = n1+n2−2

= 15+12−2=27−2=25

Therefore, the degrees of freedom associated with the critical value is 25.

4 0

3 years ago

I got the first part but cant figure out the second, help would be appreciated

azamat

Answer:

see explanation

Step-by-step explanation:

look at the explanation& answer photo

6 0

3 years ago