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Julli [10]
3 years ago
8

Which is smaller: 5 nanometers or 50 micrometers

Mathematics
2 answers:
lina2011 [118]3 years ago
8 0
5 nanometers is smaller
Talja [164]3 years ago
6 0

recall that the larger the denominator, the smaller the fraction.


\bf \stackrel{~\hfill micro~~}{10^{-6}\implies \cfrac{1}{10^6}\implies \cfrac{1}{1000000}}~~>~~10^{-9}\implies \cfrac{1}{10^9}\implies \stackrel{nano}{\cfrac{1}{1000000000}}

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First one please thanksssa
serious [3.7K]

In order to find this, we need to count exactly how many times each of them blinks within 60 seconds. Then, we find which numbers are the same.

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60

6, 12, 18, 24, 30, 36, 42, 48, 54, 60

Now, I will bold the numbers that are the same.

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60

6, 12, 18, 24, 30, 36, 42, 48, 54, 60

Now, we have our answer.

Answer: The two neon lights will blink on the 12, 24, 36, 48, and 60 second marks.

Hope I helped!

5 0
3 years ago
5^7/5^5 hurrrrrrrrryyyyyyyyyyyyy
Gnoma [55]

Answer:

25

Step-by-step explanation:

8 0
3 years ago
How can you estimate 74.3 divided by 8
Greeley [361]
The answer of 74 divided by 8 hope this helps
7 0
3 years ago
Could you please help me for this question?
Olin [163]

Answer:

  See attached for graphs

  g(x) -- domain: -∞ < x < ∞; range: 0 < y < ∞

  g^-1(x) -- domain: 0 < x < ∞; range: -∞ < y < ∞

Step-by-step explanation:

g(x) is an exponential decay function. Its base is 1/3, so each increase of 1 unit in x will multiply the y-value by a factor of 1/3. The graph will rapidly approach its horizontal asymptote of y=0 as x gets large. The y-intercept is (0, 1). Just as y gets smaller as x increases, so it gets larger as x decreases. Each decrease of x by 1 unit causes the y-value to be multiplied by 3.

__

The graph of g^-1(x) is the graph of g(x) reflected across the line y=x. That is, each coordinate pair (x, y) on the graph of g(x) becomes a point (y, x) on the graph of the inverse function. In order to graph g^-1(x), you don't need to write down the function, you only need to know the relationship between the graphs.

Just as x- and y- are interchanged on the graph, so the domain, range, and intercepts are interchanged. g^-1(x) will have a vertical asymptote of x=0, and an x-intercept of (1, 0). The domain of g^-1(x) is the range of g(x): 0 < x < ∞; and the range of g^-1(x) is the domain of g(x): -∞ < y < ∞.

__

The attached graph shows g(x) in red and g^-1(x) in blue. As you can see, we created the graph simply by interchanging x and y. The line y=x is shown for reference, so you can see that each curve is a reflection of the other across that line.

_____

<em>Additional comment</em>

The explicit expression for g^-1(x) can be found by solving for y:

  x = g(y)

  x=\left(\dfrac{1}{3}\right)^y=\dfrac{1}{3^y}=3^{-y}\\\\ \log(x)=-y\cdot\log(3)\qquad\text{take logarithms}\\\\y=-\dfrac{\log{x}}{\log{3}}=-\log_3{x}\qquad\text{use the change of base relation}\\\\\boxed{g^{-1}(x)=-\log_3{x}}

If you're familiar with the log function, you know it has an x-intercept of 1 and a vertical asymptote at x=0. The base of the log function is simply a vertical scale factor. The minus sign reflects it across the x-axis.

6 0
2 years ago
I NEED HELP PLEASE IM BEGGING YOU
horrorfan [7]

Answer:

$2

$1.26

Step-by-step explanation:

pls give brainliest if you can

8 0
2 years ago
Read 2 more answers
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