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Lemur [1.5K]
2 years ago
11

Can someone tell ne how to draw graph with equations​

Mathematics
1 answer:
miss Akunina [59]2 years ago
5 0

Answer:

ya!

Step-by-step explanation:

Find in the attachment

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Which of the following statements about the picture is true
Contact [7]

Answer:

  (c)  Point A is not on a bisector

Step-by-step explanation:

The figure shows you AR > AT. Since AX is the same for both triangles, angle AXR must be greater than angle AXT. This means AX is not the bisector of angle X.

Since AT is perpendicular to XT, it cannot be the perpendicular bisector of XT. That bisector will intersect XT at its midpoint, not its end.

The marked distances show you that A is different distances from T and R.

The only statement that makes any sense is ...

  Point A is not on a bisector.

7 0
2 years ago
Help ya’ll smart people help me
torisob [31]

Answer:

1) -200

2) -126

3) -5 + (-10)

4) -10

5) -60 + (-85) + (-115) = -260

Step-by-step explanation:

You can just add all of them normally then add the negative sign (-) at the end.

Hope this helps!

3 0
3 years ago
Lim <br> θ→0 <br> cos(7θ) − 1/sin(5θ)
egoroff_w [7]
This was 4 days ago!!!!!!
6 0
3 years ago
The thickness of a plastic film (in mils) on a substrate material is thought to be influenced by the temperature at which the co
statuscvo [17]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if rising the process temperature reduces the thickness of the plastic film that coats a substrate material To do so, two samples of substrates are coated at different temperatures:

Sample 1

X₁: Thickness of the plastic film after the substrate is coated at 125F

n₁=11

X[bar]₁= 101.28

S₁= 5.08

Sample 2

X₂: Thickness of the plastic film after the substrate is coated at 150F

n₂= 13

X[bar]₂= 101.70

S₂= 20.15

Does the data support this claim? Use the P-value approach and assume that the two population standard deviations are not equal.

Now if the higher the heat, the thinner the thickness of the plastic coating, then the average thickness of the coating done at 150F should be less than the average thickness of the coating done at 125F, symbolically: μ₂ < μ₁

Then the hypotheses are:

H₀: μ₂ ≥ μ₁

H₁: μ₂ < μ₁

α:0.05 (there is no α level stated so I've chosen the most common one)

Assuming that both variables have a normal distribution since the population standard deviations are not equal, the statistic to use is the Welch's t-test:

t= \frac{(X[bar]_2-X[bar]_1)-(Mu_1-Mu_2)}{\sqrt{\frac{S^2_1}{n_1} +\frac{S^2_2}{n_2} } } ~~t_w

t_{H_0}= \frac{(101.7-101.28)-0}{\sqrt{\frac{(20.15)^2}{13} +\frac{(5.08)^2}{11} } } = 0.072

This test is one-tailed to the left, meaning that you'll reject the null hypothesis at small values of t. The p-value is also one-tailed and has the same direction as the test. To calculate it you have to first calculate the degrees of freedom of the Welch's t:

Df_w= \frac{(\frac{S^2_1}{n_1} +\frac{S^2_2}{n_2} )^2}{\frac{(\frac{S^2_1}{n_1})^2 }{n_1-1}+\frac{(\frac{S^2_2}{n_2} )^2}{n_2-1}  }

Df_w= \frac{(\frac{5.08^2}{11} +\frac{20.15^2}{13} )^2}{\frac{(\frac{5.08^2}{11})^2 }{10} +\frac{(\frac{20.15^2}{13} )^2}{12} } = 13.78

The distribution is a Student's t with 13 degrees of freedom, then you can calculate the p-value as:

P(t₁₃≤0.072)= 0.4718

Using the p-value approach, the decision rule is:

If the p-value ≤ α, the decision is to reject the null hypothesis.

If the p-value > α, the decision is to not reject the null hypothesis.

The p-value is greater than the significance level, so the decision is to nor reject the null hypothesis.

Using a significance level of 5%, there is no significant evidence to support the claim that the average thickness pf the plastic coat processed at 150F is less than the average thickness pf the plastic coat processed at 125F.

I hope you have a SUPER day!

4 0
3 years ago
A map has a scale of 1 in: 10 mi. On the map, the distance between two cities is 5 inches. What is the actual distance between t
Schach [20]
50 miles since 1 inch equals 10 miles and there's 5 inches that means 5x10=50
4 0
3 years ago
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