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Sever21 [200]
3 years ago
14

A local pizza shop has a membership program for frequent buyers. The membership costs $10 per month and members get a discounted

price of $1.75 per slice of pizza. Autumn purchased a membership to this pizza shop.What would be the monthly cost for xx slices of pizza?
Mathematics
1 answer:
dmitriy555 [2]3 years ago
8 0

Answer:

Monthly cost = $10 + $1.75x

Step-by-step explanation:

Given the following :

Membership cost = $10 per month

Discounted price for members = $1.75 per slice of pizza

If Autum purchased the membership, the monthly cost for x slices of pizza

Monthly cost of x slices will be :

Membership cost + (discounted price * number of slices)

Monthly cost = $10 + ($1.75 * x)

Monthly cost = $10 + $1.75x

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the first one

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Inverse laplace of [(1/s^2)-(48/s^5)]
Katen [24]
**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform F(s) and G(s), then \mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}

Given that \dfrac{1}{s^2} = \dfrac{1!}{s^2} and -\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}

So you have \mathcal{L}^{-1}\left\{\dfrac{1}{s^2} - 2\cdot\dfrac{4!}{s^5}\right\} = \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\}

From Table of Laplace Transform, you have \mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}} and hence \mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n

So you have \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}.

Hope this helps...
7 0
3 years ago
Nick has designed a diamond shaped kite as shown below. The measures of some sides of the kite are marked in the figure. Find th
Zepler [3.9K]

Answer:

<h2>x = 3.499 in</h2>

Step-by-step explanation:

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       DC=7\text{ }in,\text{ }OC=5\text{ }in

From Pythagoras theorem, since \Delta DOC is a right angled triangle, DO^{2}+OC^{2}=DC^{2}.

      Area of \Delta DOC = \frac{1}{2}\times base\times height

=\frac{1}{2}\times DO\times OC=\frac{1}{2}\times OP\times DC\\(2\sqrt{6})\times(5)=(7)\times(OP)\\OP=3.499\text{ }in

From diagram OP=x

∴ x=3.499\text{ }in

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Answer:

The slope is negative. The relationship is proportional

Step-by-step explanation:

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