Answer:
a₁₀₀ = 697
Step-by-step explanation:
The nth term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 4 and d = a₂ - a₁ = 11 - 4 = 7 , then
a₁₀₀ = 4 + (99 × 7) = 4 + 693 = 697
if the number 517*324 is completely divisible by 3, then what is the smallest whole number that could replace the *?
1 answer:
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