Answer:
2002 pounds
Explanation:
To know the weight of the plane, we need to find an equation that relates the amount of fuel to the weight.
This equation can be founded using the following
Where m is the slope, x1 is the number of gallons and y1 is the respective weight. So, replacing m = 6.0, x1 = 51 gallons and y1 = 2206 pounds, we get:
Now, we can solve for y
Then, we can calculate the weight of an airplane with 17 gallons of fuel replacing x = 17 on the equation above
y = 6x + 1900
y = 6(17) + 1900
y = 102 + 1900
y = 2002
Therefore, the answer is 2002 pounds
Answer:
The absolute error of the measurement is 0.25 inches
Step-by-step explanation:
we know that
The absolute error of a measurement is equal to one half the unit of measure.
In this problem we have
7.5 inches
The measurement is given by 0.5 inches
So
the absolute error of this measurement is
Therefore
the exact measurement could be between
7.5 (+/-) 0.25 in
That is, between 7.25 in and 7.75 in
We can do this by converting the equation to vertex form:-
h = -16t^2 + 36t + 10
= -16(t^2 - 2.25t) + 10
= -16 [ (t - 1.125)^2 - (1.125)^2] + 10
= -16(t - 1.125)^2 + 20.25 + 10
= -16(t - 1.125)^2 + 30.25
So the answer is 1.13s and 30.25 ft.
= (
Answer:
Before we graph we know that the slope, mx, could be read as . To graph the the equation of the line, we begin at the point (0,0). From that point, because our rise is negative (-1), instead of moving upwards or vertically, we will move downards. Therefore, from point 0, we will vertically move downwards one time. Now, our point is on point -1 on the y-axis. Now, we have 2 as our run. From point -1, we move to the right two times. We land on point (2,-1). Because we need various points to graph this equation, we must continue on. In the end, the graph will look like the first graph given.
For the equation y = 2, the line will be plainly horizontal. Why? Because x has no value in the equation. The variable does not exist in this linear equation. Therefore, it will look like the second graph below. We graph this by plotting the point, (0,2), on the y-axis.