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tangare [24]
2 years ago
15

Numbers between 61 and 107 that is a multiple of 3, 6, and 8

Mathematics
1 answer:
alexandr1967 [171]2 years ago
3 0
72 and 96 are divisible by 3, 6, and 8.
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BRAINLIEST!!!!
lana66690 [7]
Both Aliyah and Ivan are correct because both chose the correct scale factor for the dilation and both describe other transformations that would produce triangle <span>.  </span>
7 0
3 years ago
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What is the meaning of an absolute value
storchak [24]

Answer:

"Absolute value" is the non-negative value of a number, disregarding whether or not it has a sign.

Step-by-step explanation:

"Absolute value" is the non-negative value of a number, disregarding whether or not it has a sign. It can be thought of as how far it is away from the number of 0, whether it's to the left or right. Absolute value of a number is written as |x|, where x = any number. Let's say x was -1. |-1| would be 1 because it's 1 away from 0. If x was just 1, then the number would stay the same.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

6 0
2 years ago
Which expression is NOT equivalent to -6 x (1/3 + 1/3)
Natalka [10]
A -6/3 + 1/3 I believe is the answer
6 0
2 years ago
The first four ionization energies in kj/mol of a certain second- row element are 900, 1757, 14,849, and 21,007. what is the lik
ki77a [65]

Answer:<em> Berylium (Be)</em>

Step-by-step explanation:

The <em>first ionisation energy</em> is the energy required to remove one mole of the outermost electrons from one mole of gaseous atoms.

<em />

<em> Second, third, and fourth ionisation</em> energies are the energies required to remove the succesive mole of electrons of the same atoms

Successive ionisation energies are larger because, <em>once you have removed the first electron you get a positive ion</em>. Removing an electron (which is a negative charge) from a positive ion is more difficult than removing it from the neutral atom. And removing an electron from an ion with 2⁺ or  3⁺ charges is increasingly difficult.

When you find a large jump from one inoization energy to the succesive one you can predict that you are removing an electron from a closer to the nucleus orbital.

Berylium has atomic number 4. So, the number of electrons of the neutral atom is also 4. Hence, the electron configuration of beryllium is 1s² 2s².

From the given data, <em>the first four ionization energies in kJ/mol are 900, 1757, 14,849, and 21,007</em>.

From that you can calculate the following changes in the ionization energies:

  • From first to second: 1,757 kJ/mol - 900 kJ/mol = 857 kJ/mol
  • From second to third: 14,849 kJ/mol - 1,757kJ/mol = 13,092 kJ/mol
  • From third to fourth: 21,007 kJ/mol - 14,849 kJ/mol = 6,158 kJ/mol

And now you can see that there is a larger jump in the energy, a greater change, required to remove the third electron.

That is explained because the first and second electron are removed from the orbital 2s while the third electron has to be removed from the orbital 1s which is closer to the nucleus. This third electron is more strongly attracted by the nucleus and substantially  more energy is required to accomplish this work.

5 0
3 years ago
Read 2 more answers
Help ill give u 25 points
enyata [817]

Answer:

Step-by-step explanation:

1) 2^1 = 2, 2^2=4, 2^3=8 2^4=6 2^5=2 .. we can find out a pattern: 2,4,8,6,2,4..

so 2^30 (mod 10) = 2^2 (mod 10) = 4

2) similar to Q1, 7^1 = 7, 7^2 = 9, 7^3 = 3, 7^4,=1, 7^5 = 7, the pattern is: 7,9,3,1,7.. so 7^28 = 7^4 = 1

3) since any power of 5 is equal to 5, (5^2005)-5 (mod 10) = 5-5 = 0

4) since any power of 1 is equal to 1, and there is a pattern for the power of 4 that is 4,6,4,6.. so (11^2005)-4^2005 = 1 - 4 (mod 10) = 7

5) 8's pattern is 8,4,2,6 and 3's pattern is 3,9,7,1, so (8^15)-3^7 = 2 - 7 = 5

6) 3's pattern is 3,9,7,1, so (3^75) (mod 10) = 7

8 0
2 years ago
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