All categories

2 years ago

What is the average rate of change for this quadratic function for the interval

Mathematics

2 answers:

hjlf2 years ago

7 0

Answer:

hi the answer should be C or 8

Step-by-step explanation:

Hope this helps!

zvonat [6]2 years ago

5 0

Answer:

Step-by-step explanation:

The average rate of change is given by

f(x2) -f(x1)

---------------

x2-x1

x2 = -3 and x1 = -5

Looking at the graph

f(x2) = f(-3) = 1

f(x1)= f(-5) =-15

Substituting these values into the equation

1 - (-15)

---------------

-3 - (-5)

1+15

----------

-3 +5

----

You might be interested in

Suppose X and Y represent two different school populations where X > Y and X and Y must be greater than 0. Which of the follo

Stells [14]

Answer:(X+Y)²

X²+Y² would be greater than X²-Y² since addition gives a greater result than subtraction.

X²+Y² would be greater than 2(X+Y); this is because 2(X+Y) = 2X+2Y, which will be less than X²+Y², since X>Y.

(X+Y)² = (X+Y)(X+Y). This can be simplified using the distributive property:

X(X)+X(Y)+Y(X)+Y(Y) = X²+XY+YX+Y² = X²+2XY+Y². This is greater than X²+Y².

7 0

3 years ago

Read 2 more answers

Round your answer to the nearest tenth if necessary. Use 3.14 for it.

aliina [53]

Answer:

volume = 10,082.5 in³

Step-by-step explanation:

radius = 26/2 = 13

volume = πr²L = (3.14)(13²)(19) = 10,082.54 in³

6 0

3 years ago

Help me plzzzzzzzzzzzzzz

notsponge [240]

I think it’s the bottom one

3 0

2 years ago

Read 2 more answers

What is the X for this 7x+12=26

lukranit [14]

Answer:

x = 2

Step-by-step explanation:

$7x + 12 = 26 \\ subtract \: 12 \: from \: both \: side \\ 7x = 14 \\ divide \: both \: side \: by \: 7 \\ x = 2$

7 0

2 years ago

One tank is filling at a rate of 5/8 gallon per 7/10 hour. A second tank is filling at a rate of 5/9 gallon per 2/3 hour. Which

anzhelika [568]

First recognize that the unit rate we're finding is gallons per hour, or $\frac{g}{h}$ .

rate for Tank 1 = x gallons per hour = a gallons / b hours

$T_{1}=\frac{\frac{5}{8}}{\frac{7}{10}}\\\\T_{1}=\frac{5}{8}*\frac{10}{7}\\\\T_{1}=\frac{50}{56}\\\\\\Fill\ rate\ of\ Tank\ 1=\frac{25}{28}$

rate for Tank 2 = y gallons per hour = c gallons / d hours

$T_{2}=\frac{\frac{5}{9}}{\frac{2}{3}}\\\\T_{2}=\frac{5}{9}*\frac{3}{2}\\\\T_{2}=\frac{15}{18}\\\\T_{2}=\frac{15}{18}\\\\\\Fill\ rate\ of\ Tank\ 2=\frac{5}{6}$

3 0

3 years ago