Answer:
View Image
x = π/6, 5π/6, 7π/6, 11π/6
Step-by-step explanation:
The only things you need to know are 2 things:
1.) , the exponent of trig functions are written in the middle
2.) , csc() is just the inverse of sin()
Pls help me! I’ll help u if u do!!
1 answer:
Answer:
a) $160
b) $116.50
Step-by-step explanation:
a) Let the original price of the yellow bicycle be $x.
Since both has the same original price,
original price of yellow bicycle= 100% x
original price of green bicycle= 100% x
Discounted price of yellow bicycle
= (100% -25%) x
= 75% x
Discounted price of green bicycle
= (100% -30%) x
= 70% x
Difference in cost
= 75%x -70%x
= 5% x -----(1)
From 2nd paragraph:
Discounted price of yellow bicycle
= Kyreen's money +3.50
Discounted price of green bicycle
= Kyreen's money -4.50
Difference in cost
= (Kyreen's money +3.50) -(Kyreen's money -4.50)
= Kyreen's money +3.50 -Kyreen's money +4.50
= 3.50 +4.50
= 8.00 -----(2)
Equating (1) and (2) together:
5% x= 8.00
x= 8 ×20
x= 160
Thus, the original price of the yellow bicycle is $160.
_______
b) Amount Kyreen has at first
= discounted price of yellow bicycle -$3.50
= 75%($160) -$3.50
= $120 -$3.50
= $116.50
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| 2 -7 8 -3
<u>1 | 2 -5 3</u>
| 2 -5 3 0
<u> 1 | 2 -3 </u>
2 -3 0
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Synthetic division is used since the equation is of the third degree. The divisors of -4 are 1, -1, 2, -2, 4, -4. So:
| 1 -1 0 -4
<u>2 | 2 2 </u>
1 2 2 0
So the factorization is (x-2)(x²+x+2)=0 . When calculating the discriminant of the trinomial, it is concluded that it has no roots since the result is negative. So you only have one solution.
Synthetic division is used since the equation is of the third degree. The divisors of 2 are 1, -1, 2, -2. So:
| 6 7 9 2
<u>-2 | -12 10 -2</u>
6 -5 1 0
So the factorization is (x+2)(6x²-5x+1)=0 . The quadratic equation is solved by the general formula:
Answer:
The graph is sketched by considering the integral. The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.
Step-by-step explanation:
We sketch the integral ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ. We consider the inner integral which ranges from r = 0 to r = 6/cosθ. r = 0 is located at the origin and r = 6/cosθ is located on the line x = 6 (since x = rcosθ here x= 6)extends radially outward from the origin. The outer integral ranges from θ = 0 to θ = π/4. This is a line from the origin that intersects the line x = 6 ( r = 6/cosθ) at y = 1 when θ = π/2 . The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.
