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Aloiza [94]
3 years ago
10

Please Help!!

Physics
1 answer:
olchik [2.2K]3 years ago
6 0

Answer:

\boxed {\boxed {\sf 15 \ m/s^2 \ to \ the \ right}}

Explanation:

We are asked to find the acceleration of a box.

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

F=ma

The mass of the box is 5 kilograms. There are two forces applied: a 25 Newton force and a 50 Newton force, both applied right. Since they are applied in the same direction, we can add them.

  • 25 N right + 50 N right = 75 N right.

Now we know 2 of the variables in the formula:

  • F= 75 N or 75 kg*m/s²
  • m= 5 kg

Substitute the values into the formula.

75 \ kg*m/s^2 = 5 \ kg *a

We are solving for a, so we must isolate the variable. It is being multiplied by 5 kilograms. The inverse operation of multiplication is division. Divide both sides by 5 kg.

\frac {75 \ kg*m/s^2}{5 \ kg}= \frac {5 \ kg *a}{5 \ kg}

\frac {75 \ kg*m/s^2}{5 \ kg}=a

The units of kilograms cancel.

\frac {75 m/s^2}{5}=a

15 \ m/s^2 =a

The acceleration is in the same direction as the force, so the acceleration is <u> 15 meters per second squared to the right.</u>

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