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kramer
4 years ago
8

The picture shown shows a practical application of

Physics
1 answer:
Firlakuza [10]4 years ago
7 0

Answer:

c. nuclear energy

Explanation:

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Rest and motion are relatives terms justify the statement​
Anna007 [38]

Answer:

rest and motion are the relative terms because they depend on the observer's frame of reference. So if two different observers are not at rest with respect to each other, then they too get different results when they observe the motion or rest of a body

Explanation:

3 0
3 years ago
What visible wavelengths of light are strongly reflected from a 390-nm-thick soap bubble?
DiKsa [7]

Answer:

So visible wavelength which is possible here is

416 nm and 693.3 nm

Explanation:

As we know that for normal incidence of light the path difference of the reflected ray is given as

2\mu t + \frac{\lambda}{2} = \Delta x

so here we can say that for maximum intensity condition we will have

\Delta x = N\lambda

so we have

2\mu t + \frac{\lambda}{2} = N\lambda

now for visible wavelength we have

for N = 1

2\mu t = \frac{\lambda}{2}

\lambda = 4\mu t

\lambda = 4(\frac{4}{3})(390 nm)

\lambda = 2080 nm

for N = 2

\lambda = \frac{4\mu t}{3}

\lambda = \frac{4(\frac{4}{3})(390 nm)}{3}

\lambda = 693.3 nm

for N = 3

\lambda = \frac{4\mu t}{5}

\lambda = \frac{4(\frac{4}{3})(390 nm)}{5}

\lambda = 416 nm

6 0
4 years ago
When sighting a firearm using an open sight, in what direction should the rear sight be moved if you want the shot to travel to
sattari [20]

Explanation:

Test to see where the bullets gather on your target after shooting a number of shots. Change the targets of your weapon if the bullets are not in the target's middle. Try to shift the rear view in the same direction with an open sight that you would like to push the shots on the target.

After the rifle is sighted-in, one must practice firing under various lighting and weather conditions, and at different distances to be able to become accurate and proficient shooter.

3 0
3 years ago
A package was determined to have a mass of 5.7 kilograms. What's the force of gravity acting on the package on earth?
Arturiano [62]
1.) The force of gravity is what we call weight, we define it as:
w=mg
w=5,7kg*9,8m/s²
w=55,86kg (b)
2.) We know that:
power=W/t
power=50J/20s
power=2,5Watts (a)
3.) The work done is equal to the potential energy, so:
Epg=mgh
Epg=63kg*9,8m/s²*7m
Epg=4321J
Now we get the power:
power=W/t
power=4321J/5s
power=864Watts
Now:
1HP=746Watts
=1,16HP (b)
4.) We know that:
F=ma
350N=m*10m/s²
m=350N/10m/s²
m=35kg (b)
5.) d.) Aceleration is tha rate of change in velocity, either positive (increasing) or negative (decreasing)
8 0
3 years ago
Read 2 more answers
As the temperature of an object rises, so does the.....
Karolina [17]
<span>the potential energy of the object.</span>
5 0
4 years ago
Read 2 more answers
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