Answer:
a) 31.4 m/s
b) 50.2 m
Explanation:
a) When an object is free falling, its speed is determined by the gravity force giving it acceleration. Equation for the velocity of free fall started from the rest is:
v = g • t
g - is gravitational acceleration which is 9.81 m/s^2, sometimes rounded to 10
t - is the time of free fall
So:
v = 9.81 m/s^2 • 3.2
v = 31.4 m/s ( if g is rounded to 10, then the velocity is 10 • 3.2 = 32 m/s)
b) To determine the distance crossed in free fall we use the equation:
s = v0 + gt^2/2
v0 - is the starting velocity (since object started fall from rest, its v0 is 0)
s = gt^2/2
s = 9.81 m/s^2 • 3.2^2 / 2
s = 50.2 m (if we round g to 10 then the distance is 10 • 3.2^2/2 = 51.2 meters)
First, solve for the acceleration of the car. You know the mass of the car and the braking force, so you can use the equation Force = Mass x Acceleration. This gives you 12,000 = 2,000 x A. Divide 12,000 by 2,000 to find the acceleration equal to 6 m/s^2. This is the rate that the car is slowing down at. Velocity is equal to accleration x time (rate x time), so you multiply 6 by the time of 5 seconds. This leaves you with a velocity of 30 m/s or about 67.1 mph.
Answer:
![I = 0.0256 A](https://tex.z-dn.net/?f=I%20%3D%200.0256%20A)
Explanation:
Given,
Magnetic field, B = 5 x 10⁻⁵ T
Number of turns, N = 450
length = 29 cm
Current,I = ?
Using formula of magnetic field due to solenoid
![B = \mu_0 NI](https://tex.z-dn.net/?f=B%20%3D%20%5Cmu_0%20NI)
![I = \dfrac{B}{\mu_0N}](https://tex.z-dn.net/?f=I%20%3D%20%5Cdfrac%7BB%7D%7B%5Cmu_0N%7D)
![I = \dfrac{5\times 10^{-5}\times 0.29}{450\times 4\pi \times 10^{-7}}](https://tex.z-dn.net/?f=I%20%3D%20%5Cdfrac%7B5%5Ctimes%2010%5E%7B-5%7D%5Ctimes%200.29%7D%7B450%5Ctimes%204%5Cpi%20%5Ctimes%2010%5E%7B-7%7D%7D)
![I = 0.0256 A](https://tex.z-dn.net/?f=I%20%3D%200.0256%20A)
Hence, the current obtained is equal to 0.0256 A.
Answer:
assembled
Explanation: because it was last weekend it was in the past so the past tense of assembled must be used