Question

Help with Similarity Triangles Geometry. I dont understand how to solve for x on this one.​

Answer 1

since we know those two triangles are similar then we can use proportions.

$\cfrac{AE}{AB}=\cfrac{AD}{AC}\implies \cfrac{14-8}{2x}=\cfrac{14}{2x+4}\implies \cfrac{6}{2x}=\cfrac{14}{2x+4}\implies \cfrac{3}{x}=\cfrac{14}{2x+4} \\\\\\ 6x+12=14x\implies 12=8x\implies \cfrac{12}{8}=x\implies \cfrac{3}{2}=x \\\\[-0.35em] ~\dotfill\\\\ AB=2x+4\implies AB=2\left( \frac{3}{2} \right)+4\implies AB=3+4\implies AB=7$