There are two ways to do this
Method 1:
Find (f-g)(x) first
(f-g)(x) = f(x) - g(x)
(f-g)(x) = (5x^2+3) - (-2x+4)
(f-g)(x) = 5x^2+3+2x-4
(f-g)(x) = 5x^2+2x-1
Then plug in x = -3
(f-g)(-3) = 5(-3)^2+2(-3)-1
(f-g)(-3) = 5(9)+2(-3)-1
(f-g)(-3) = 45-6-1
(f-g)(-3) = 39-1
(f-g)(-3) = 38
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Method 2:
Find f(-3)
f(x) = 5x^2+3
f(-3) = 5(-3)^2+3
f(-3) = 5(9)+3
f(-3) = 45+3
f(-3) = 48
Find g(-3)
g(x) = -2x+4
g(-3) = -2(-3)+4
g(-3) = 6+4
g(-3) = 10
Subtract the two results
(f-g)(-3) = f(-3) - g(-3)
(f-g)(-3) = 48 - 10
(f-g)(-3) = 38
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Whichever method you pick, the answer is: 38
Answer:
m= 2ke/v^2
Step-by-step explanation:
Answer:
180=x+60+100
Step-by-step explanation:
Because of vertical angles the angle beside 60 is 100 and 100+60+x would equal 180 degrees
Answer:
Step-by-step explanation:
hello,
i advice you check the question again if it is GF(
) or GF(24). i believe the question should rather be in this form;
multiplication in GF(
): Compute A(x)B(x) mod P(x) =
+
+1, where A(x)=
+1, and B(x)=
.
i will solve the above question and i believe with this you will be able to solve any related problem.
A(x)B(x)=
= 
=
please note that the division by the modulus above we used
