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2 years ago

The median weight of 15 dogs in a pet store is 12 pounds. Which action could change the median?

Mathematics

1 answer:

never [62]2 years ago

7 0

Answer:

If there was another dog whose weight was greater than or less than 12.

Step-by-step explanation:

12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 4

When we add 4 to the data set we have:

184 ÷ 16 = 11.5

This changed the median.

12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 28

When we add 28 to the data set we have:

208 ÷ 16 = 13

This also changed the median.

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GuDViN [60]

Answer:

$y = \frac{1}{4} \times {2}^{x} - 1$

Step-by-step explanation:

Assuming the given logarithmic equation is

$y = \log_{2}( {4}{x } - 4)$

We interchange x and y to get:

$x= \log_{2}( {4}{y} - 4)$

We solve for y now:

${2}^{x} = {4}{y} - 4$

We add 4 to both sides to get;

${2}^{x} + 4 = 4y$

Divide through by 4:

$y = \frac{1}{4} \times {2}^{x} - 1$

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2 years ago

What is the approximate volume of a cone with a radius of 15 cm and a height of 4 cm? Round your answer to the nearest hundredth

vichka [17]

Answer:

Volume of a cone $=942.86cm^3$

Step-by-step explanation:

Given that the radius of a cone is 15cm and its height is 4cm

That is r=15cm and h=4cm

To find the volume of a cone :

volume of a cone $=\frac{\pi r^2h}{3}$ cubic units

Now substitute the values in the formula we get

volume of a cone $=\frac{(\frac{22}{7}) (15)^2(4)}{3}$

$=\frac{(\frac{22}{7}) (225)(4)}{3}$

$=\frac{19800}{21}$

$=942.857$

Now round to nearest hundredth

$=942.86$

Therefore Volume of a cone $=942.86cm^3$

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3 years ago