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Virty [35]
2 years ago
11

The median weight of 15 dogs in a pet store is 12 pounds. Which action could change the median?

Mathematics
1 answer:
never [62]2 years ago
7 0

Answer:

If there was another dog whose weight was greater than or less than 12.

Step-by-step explanation:

12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 4

When we add 4 to the data set we have:

184 ÷ 16 = 11.5

This changed the median.

12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 28

When we add 28 to the data set we have:

208 ÷ 16 = 13

This also changed the median.

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Answer:

y =  \frac{1}{4}  \times  {2}^{x}  - 1

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Assuming the given logarithmic equation is

y =   \log_{2}( {4}{x }  - 4)

We interchange x and y to get:

x=   \log_{2}( {4}{y} - 4)

We solve for y now:

{2}^{x}  =  {4}{y}   - 4

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{2}^{x}  + 4 = 4y

Divide through by 4:

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Step-by-step explanation:

Given that the radius of a cone is 15cm and its height is 4cm

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