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saveliy_v [14]
2 years ago
6

Anyone know this problem need asap

Mathematics
1 answer:
nekit [7.7K]2 years ago
3 0

Answer:

The answer to your query would be the Third Answer Choice.

Step-by-step explanation:

> First we need to find where the point (3,0) lies on the graph. We can do this by looking at the x coordinate, being 3, and the y, being 0. Keep in mind that the solution is where the two lines meet, not where the point on the graph is.

> This gets us to 3 on the x line, and no further. We then need to find which has an intersection of both lines on that point. If it is not (0,3), it is not the correct answer, which we are looking for.

> The first graph has a solution of (0, -1.5), as this is where the lines intersect. This is not (3, 0), so this is not our answer.

> The second graph’s lines intersect at (0,1), and since that is the solution of the graph, it is not the correct answer.

> The third graph’s lines intersect at (3, 0), and since this is it’s solution, it is the correct answer. Since we cannot be 100% sure, we still need to continue with checking the last graph.

> The fourth and last graph’s lines meet at (0,3), which is not what we are looking for, and is henceforth wrong.

> Once again, the correct answer is the Third Answer Choice. All the other graph’s have solutions on points other than (3,0), so they are not our answers.

> I hope this answered your query and any other questions you may have had on the subject. #LearningWithBrainly

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Answer:

60

Step-by-step explanation:

3 0
2 years ago
On a coordinate plane, an image rectangle has points (negative 5, 0), (5, 0), A prime (5, negative 5), (negative 5, negative 5).
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Answer:(5/3,5/3)

Step-by-step explanation: I did the test ;D

6 0
3 years ago
Read 2 more answers
Lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. a bank conducts inter
Otrada [13]
Part A:

Given that lie <span>detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector correctly determined that a selected person is saying the truth has a probability of 0.85
Thus p = 0.85

Thus, the probability that </span>the lie detector will conclude that all 15 are telling the truth if <span>all 15 applicants tell the truth is given by:

</span>P(X)={ ^nC_xp^xq^{n-x}} \\  \\ \Rightarrow P(15)={ ^{15}C_{15}(0.85)^{15}(0.15)^0} \\  \\ =1\times0.0874\times1=0.0874
<span>

</span>Part B:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.25
Thus p = 0.15

Thus, the probability that the lie detector will conclude that at least 1 is lying if all 15 applicants tell the truth is given by:

P(X)={ ^nC_xp^xq^{n-x}} \\ \\ \Rightarrow P(X\geq1)=1-P(0) \\  \\ =1-{ ^{15}C_0(0.15)^0(0.85)^{15}} \\ \\ =1-1\times1\times0.0874=1-0.0874 \\  \\ =0.9126


Part C:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.15
Thus p = 0.15

The mean is given by:

\mu=npq \\  \\ =15\times0.15\times0.85 \\  \\ =1.9125


Part D:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.15
Thus p = 0.15

The <span>probability that the number of truthful applicants classified as liars is greater than the mean is given by:

</span>P(X\ \textgreater \ \mu)=P(X\ \textgreater \ 1.9125) \\  \\ 1-[P(0)+P(1)]
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</span>P(1)={ ^{15}C_1(0.15)^1(0.85)^{14}} \\  \\ =15\times0.15\times0.1028=0.2312<span>
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3 years ago
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The rope length is 50 feet again, thus the results are the same.
 
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8 0
3 years ago
Write 0.126126126... as a fraction​
Alchen [17]

Answer:

x = 126/999

Step-by-step explanation:

Let x = .126126126 repeating

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1000x = 126.126126126 repeating

- x = .126126126 repeating

999x = 126

Divide each side by 999

999x/999 = 126/999

x = 126/999

4 0
3 years ago
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