We will have a system of equations, and we are going to solve it by using substitution.
Let's make the equations.
x+y+z=2100
z+y=x
Since y and z are equal, I think it is easier for us to have them as one variable for now. Let the value of z and y be a.
These are the equations now.
x+2a=2100
2a=x
Since the second equation is giving the value of x, let it replace the value of x also in the first equation.
2a+2a=2100
4a=2100
2100÷4= 525
so, x and y equal 525. Let's put this in our original equation.
x+525+525=2100
x+ 1,050= 2,100
x= 1,050
So, x=1,050, y= 525 =z.
Answer:
6 and -6
Step-by-step explanation:
3+2=5
Answer:
max is 25 there is no min
Step-by-step explanation:
max is 25 because when you do the table the highest y value their is it is 25 the min they are the same so there is no absolute min
Answer:
![Weight = \frac{23}{2}](https://tex.z-dn.net/?f=Weight%20%3D%20%5Cfrac%7B23%7D%7B2%7D)
Step-by-step explanation:
Given
Weight of Pinata = 11/4 lb
Weight of candies = 3/8, 3/8, 1/2 , 1/2, 1/2, 3/4, 3, 11/4
Required
Weight of Pinata when filled with candies
To solve this question, we simply need to add all weights together
First, we need to add up the weight of the candies
![Candies = \frac{3}{8} + \frac{3}{8} + \frac{1}{2}+ \frac{1}{2}+ \frac{1}{2}+ \frac{3}{4} + 3 + \frac{11}{4}](https://tex.z-dn.net/?f=Candies%20%3D%20%20%5Cfrac%7B3%7D%7B8%7D%20%2B%20%5Cfrac%7B3%7D%7B8%7D%20%2B%20%5Cfrac%7B1%7D%7B2%7D%2B%20%5Cfrac%7B1%7D%7B2%7D%2B%20%5Cfrac%7B1%7D%7B2%7D%2B%20%5Cfrac%7B3%7D%7B4%7D%20%2B%203%20%2B%20%5Cfrac%7B11%7D%7B4%7D)
Take LCM
![Candies = \frac{3 + 3 + 4 +4 + 4 + 6 + 24 + 22}{8}](https://tex.z-dn.net/?f=Candies%20%3D%20%5Cfrac%7B3%20%2B%203%20%2B%204%20%2B4%20%2B%204%20%2B%206%20%2B%2024%20%2B%2022%7D%7B8%7D)
![Candies = \frac{70}{8}](https://tex.z-dn.net/?f=Candies%20%3D%20%5Cfrac%7B70%7D%7B8%7D)
Simplify:
![Candies = \frac{35}{4}](https://tex.z-dn.net/?f=Candies%20%3D%20%5Cfrac%7B35%7D%7B4%7D)
Next; Add the weight of the candies to the weight of pinata
![Weight = Candies + Pinata](https://tex.z-dn.net/?f=Weight%20%3D%20Candies%20%2B%20Pinata)
![Weight = \frac{35}{4} + \frac{11}{4}](https://tex.z-dn.net/?f=Weight%20%3D%20%5Cfrac%7B35%7D%7B4%7D%20%2B%20%5Cfrac%7B11%7D%7B4%7D)
Take LCM
![Weight = \frac{35 + 11}{4}](https://tex.z-dn.net/?f=Weight%20%3D%20%5Cfrac%7B35%20%2B%2011%7D%7B4%7D)
![Weight = \frac{46}{4}](https://tex.z-dn.net/?f=Weight%20%3D%20%5Cfrac%7B46%7D%7B4%7D)
Simplify
![Weight = \frac{23}{2}](https://tex.z-dn.net/?f=Weight%20%3D%20%5Cfrac%7B23%7D%7B2%7D)
<em>Hence, the weight of the Pinata after it is filled with candies is 23/2 lb</em>
Answer:
42 students
Step-by-step explanation: