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wlad13 [49]
2 years ago
5

it takes a 1/4 bottle glue to make slime if teacher has 15 bottles of glue how many bottles of slime can the 5th graders make

Mathematics
1 answer:
tangare [24]2 years ago
7 0

Answer:

60students

Step-by-step explanation: 4 x 15=60

This is because each bottle can make 4 slimes and if there are 15 bottles you multiply 4 by 15. Now you will receive 60.

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A recent health report revealed that a woman with insurance spends an average of 2.3 days in the hospital following a routine ch
cupoosta [38]

Answer:

t=\frac{2.3-1.9}{\sqrt{\frac{0.6^2}{16}+\frac{0.3^2}{16}}}}=2.385  

p_v =2*P(t_{30}>2.385)=0.0236

Comparing the p value with the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis

The confidence interval would be given by:

(2.3 -1.9) - 2.75*\sqrt{\frac{0.6^2}{16}+\frac{0.3^2}{16}}}=-0.0611

(2.3 -1.9) + 2.75* \sqrt{\frac{0.6^2}{16}+\frac{0.3^2}{16}}}=0.861

Step-by-step explanation:

Data given and notation

\bar X_{insurance}=2.3 represent the mean for insurance

\bar X_{No. ins}=1.9 represent the mean withour insurance

s_{Insurance}=0.6 represent the sample standard deviation for the insurance case

s_{No. Ins}=0.3 represent the sample standard deviation for the No insurance case

n_{Insurance}=16 sample size for insurance

n_{No. Iss}=16 sample size for no insurance

t would represent the statistic (variable of interest)

\alpha=0.01 significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the means for the two groups are different, the system of hypothesis would be:

Null hypothesis:\mu_{Insu}=\mu_{No. Ins}

Alternative hypothesis:\mu_{Ins} \neq \mu_{No. Ins}

Since we know the population deviations for each group, for this case is better apply a z test to compare means, and the statistic is given by:

t=\frac{\bar X_{Ins}-\bar X_{No.Ins}}{\sqrt{\frac{s^2_{Ins}}{n_{Ins}}+\frac{s^2_{No. Ins}}{n_{No. Ins}}}} (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

t=\frac{2.3-1.9}{\sqrt{\frac{0.6^2}{16}+\frac{0.3^2}{16}}}}=2.385  

What is the p-value for this hypothesis test?

The degrees of freedom are given by:

df = n_{ins} +n_{No Ins}-2=16+16-2 =30

Since is a bilateral test the p value would be:

p_v =2*P(t_{30}>2.385)=0.0236

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis

The confidence interval would be given by:

(2.3 -1.9) - 2.75*\sqrt{\frac{0.6^2}{16}+\frac{0.3^2}{16}}}=-0.0611

(2.3 -1.9) + 2.75* \sqrt{\frac{0.6^2}{16}+\frac{0.3^2}{16}}}=0.861

6 0
2 years ago
When the sun has risen 32 degrees above the horizon, Sandy casts a shadow that is 9 feet 2 inches long. How tall is Sandy, to th
Makovka662 [10]

Answer:

The height of Sandy is 68.74 inches.

Step-by-step explanation:

It is given that the sun has risen 32 degrees above the horizon. It means the angle of elevation is 32°.

Let the height of Sandy be x.

Sandy casts a shadow that is 9 feet 2 inches long.

We know that 1 feet = 12 inches

Using this conversion, we get

Shadow = 9 feet 2 inches = 9(12)+2 = 110 inches

In a right angled triangle,

\tan\theta =\frac{perpendicular}{base}

In triangle ABC,

\tan(\angle C)=\frac{AB}{BC}

\tan(32^{\circ})=\frac{x}{110}

Multiply both sides by 110.

110\tan(32^{\circ})=x

68.73562871=x

x\approx 68.74

Therefore the height of Sandy is 68.74 inches.

8 0
3 years ago
For a school event, of the athletic field is reserved for the fifth-grade classes.
Rashid [163]

Answer:

1/4

Step-by-step explanation:

4 classes, each class gets one spot!

4 0
3 years ago
Find g(1) if g(x) = x 2 + 1.
Genrish500 [490]

Answer:

g(x) = x^2 + 1

if x=1

g(1) = 1^2 + 1

g(1) = 1 + 1

g(1) = 2

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<span>The surface area of a cylinder includes the bases which are circles and the side which is a rectangle</span>
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2 years ago
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