1 is 384cm you multiply the 96 by 4 (because there is 96 4 times)
If I’m incorrect I’m sorry
Answer:
Minimum 8 at x=0, Maximum value: 24 at x=4
Step-by-step explanation:
Retrieving data from the original question:
![f(x)=x^{2}+8\:over\:[-1,4]](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%2B8%5C%3Aover%5C%3A%5B-1%2C4%5D)
1) Calculating the first derivative
2) Now, let's work to find the critical points
Set this
0, belongs to the interval. Plug it in the original function
3) Making a table x, f(x) then compare
x| f(x)
-1 | f(-1)=9
0 | f(0)=8 Minimum
4 | f(4)=24 Maximum
4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.
The gallons of oil in the tank is 1000
A 6500 gallon storage tank is 2/13 full
The number of oil in the tank can be calculated by multiplying the amount of gallons in the tank which is 6500 by the measurement of the tank which is 2/13
= 2/13 × 6500
= 13,000/13
= 1,000
Hence 1000 gallons of oil are in the tank
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- for line B so the set of equations to have no solutions bc. x+y=2 and so y=2-x
so from x+y=4 will result y=4-x
so this is the right equation for line B so the set of equations has no solutions
1+(4x) ??????????? I think so
