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Charra [1.4K]
2 years ago
12

the Gilbert family brought airline tickets online. each ticket cost $186.the website also charged a flat fee of $16 for the tran

saction. the Gilberts were charged a total of $946. write a equation to determine how many tickets the Gilberts purchased. how many tickets did they purchase.​
Mathematics
1 answer:
miskamm [114]2 years ago
7 0

Answer: x=5 or 5 Tickets

Step-by-step explanation:

186x + 16 = 946

186x + 16 = 946

          -<u>16</u>      <u>-16</u>

<u>186x</u>  = 930

186x divided by 186x = 0

930 divided by 186x = 5

Therefore our answer is, x=5 or 5 Tickets

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C) 4/(x+y)²

Step-by-step explanation:

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Then rearrange so that it is 2×2/(x+y)×(x+y) or 4/(x+y)²

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The Sum of twice a number and 5 is at most 15. What are the possible values for the number?
NISA [10]
Let's call that number x, twice the number will be 2x, sum of it and 5 is, 2x+5. So if this expression is at most 15, it means, it can be only less than 15 and equal to 15. Let's show this as an inequality.

2x+5\le 15

Let's solve.

2x+5\le 15\\ \\ 2x\le 15-5\\ \\ 2x\le 10\\ \\ x\le \frac { 10 }{ 2 } \\ \\ x\le 5

x\quad \in \quad \left[ -\infty ,5 \right]

If the number is a natural number. The values it can take is, x\quad \in \quad \left[ 0,1,2,3,4,5 \right]


6 0
3 years ago
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If a(x) = 3x + 1 and b(x)= squareroot x-4, what is the domain of (b*a)(x)?
oksano4ka [1.4K]

\boxed{ \ x \geq 1 \ } or can be written as \boxed{ \ [1, \infty) \ }

<h3>Further explanation</h3>

This is a question about the composition of functions and how to get a domain function.

Given \boxed{ \ a(x) = 3x + 1 \ } and \boxed{ \ b(x) = \sqrt{x - 4} \ }.

We will form (b o a)(x) and then determine the domain.

<u>Step-1</u>

\boxed{ \ (b \circ a)(x) = b(a(x)) \ }

Replace each appearance of x in b(x) with \boxed{ \ a(x) = 3x + 1 \ }.

\boxed{ \ (b \circ a)(x) = \sqrt{(3x + 1) - 4} \ }

Thus, \boxed{ \ (b \circ a)(x) = \sqrt{3x - 3} \ }

<u>Step-2</u>

To be defined, the value under the radical sign must not be negative. Therefore, the domain of (b \circ a)(x) = \sqrt{3x - 3} are processed as follows.

\boxed{ \ 3x - 3 \geq 0 \ }

Both sides added by 3.

\boxed{ \ 3x \geq 3 \ }

Both sides divided by 3.

\boxed{ \ x\geq 1 \ }

Thus, the domain of (b \circ a)(x) = \sqrt{3x - 3} is \boxed{ \ x \geq 1 \ } or can be written as \boxed{ \ [1, \infty) \ }

<h3>Learn more</h3>
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Keywords: composition of function, if a(x) = 3x + 1, and, b(x) = √(x-4), what is the domain of, (b o a)(x), b(a(x)), defined, the value, under the radical sign, must not be negative,

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Answer:

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Step-by-step explanation:

take the amount of each side and multiply. so it would be 5 times 7. that gives you the total area.

5 0
3 years ago
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