412 + 325 = R
R = 737
I hope that is the answer you were looking for!
Compute the gradient of 
.
Set this equal to the zero vector and solve for the critical points.
The last case has no real solution, so we can ignore it.
Now,
so we have two critical points (0, 0) and (2, 2).
Compute the Hessian matrix (i.e. Jacobian of the gradient).
Check the sign of the determinant of the Hessian at each of the critical points.
which indicates a saddle point at (0, 0);
We also have 
, which together indicate a local minimum at (2, 2).
Answer:
p = - 8
Step-by-step explanation:
we have to subtract by the number 18p from each of your sides
Like: 10p + 5 - 18p
= 18p -3 -180
This gives us: -8p + 5 = -3
Nextly, we have to subtract by 5 on each of your sides
Like: -8p + 5 - 5
= -3 - 5
This gives us: -8p = -8
Now we have divide by the -8 on each of your sides:
Like: -8p ÷ -8
= -8 ÷ -8
Answer: p = 1
Answer:
D) 4x +3y = -6
Step-by-step explanation:
paralell lines so m1 and m2 are equal
m = (3 +1 )/ (0 - 3 )
m = -4/ 3
y -2 = -4/3 (x +3)
y =-4x/3 -2
3y = -4x -6
4x +3y = -6
To get the equation of a line, you can use the following:
y - y1 = m (x - x1)
Where:
- m is the slope (2)
- y1 is the y coordinate of a point (1, -5)
- x1 is the x coordinate of the same point (1, -5)
Just substitute in the values:
y - y1 = m (x - x1)
y - (-5) = 2(x - 1) <em>( - - 5 = + 5 )</em>
y + 5 = 2(x - 1)
_________________________
Answer:
B. y + 5 = 2(x - 1)
