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Mazyrski [523]
3 years ago
15

6 divided bye 2(1+2)=???? Math math math math math math math math math math math!!!!!! :3

Mathematics
2 answers:
disa [49]3 years ago
5 0

Answer:

=  > 6 \div 2(1 + 2)

=  > 6 \div 2 \times 3

=  > 3 \times 3

=  > 9

Andre45 [30]3 years ago
4 0

Answer:

Your answer will be 9

I hope this will you

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A fish market bought two swordfish at a rate of $13 per pound. the cost of the larger fish was 3 times as great as the cost of t
oksano4ka [1.4K]
Very simple. divide 3952 by 4, because the larger fish is 3 times the amount of the small fish, so there are 4 groups. Multiply it by 3 for the larger fish and keep it for the small fish.  Then, divide the products by 13 because the quotient is the amount of money each fish costs. There you have your answer!
4 0
3 years ago
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A triangle was dilated by a scale factor of 2. If cos a° = three fifths and segment FD measures 6 units, how long is segment DE?
kiruha [24]

Answer:

10 units

Step-by-step explanation:

Given that:

Cos a = 3 /5

From trigonometry ;

Cos θ = Adjacent / hypotenus

Side Adjacent angle a = 3 = FD

Hypotenus = 5 = DE

3 / 5 = FD / DE

FD = 6 units

3/5 = 6/DE

DE * 3/5 = 6

DE = 6 ÷ 3/5

DE = 6 * 5 /3

DE = 30 /3

DE = 10 units

6 0
3 years ago
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What is the simplest form of the expression below?
sineoko [7]

Answer:

(B) cot Theta

Step-by-step explanation:

We want to simplify the expression:

\dfrac{cot\theta cos\theta}{sin\theta } X\dfrac{tan\theta}{\frac{sin\theta}{cos\theta tan \theta}  }

Now:

\dfrac{ cos\theta}{sin\theta } =cot\theta\\\dfrac{ sin\theta}{cos\theta }=tan \theta\\$Substituting these into the expression\\\dfrac{cot\theta cos\theta}{sin\theta } X\dfrac{tan\theta}{\frac{sin\theta}{cos\theta tan \theta}  }=cot\theta cot\theta X\dfrac{tan\theta}{\frac{tan\theta}{ tan \theta}  }\\=cot\theta cot\theta X tan\theta$  (Since cot\theta X tan\theta =1) \\$Therefore our result:\\=cot\theta

3 0
3 years ago
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If you know how to this and can help that would be so great...also please take a look at my last question Thanks
Alik [6]

Answer:

im sorry i dont know

Step-by-step explanation:

8 0
4 years ago
Answer the question and answer it down below
Sergio039 [100]

Answer:

4:24 p.m.

Step-by-step explanation:

Figure out how often the buses leave at the same time. This is the same as the least common multiple (LCM) of how often they leave the stadium.

The LCM is found by multiplying the maximum number of each prime factor found in any of the numbers.

The prime factors of a number are found by dividing it by whole numbers until the factors are all prime. Prime numbers only have the factors 1 and itself.

6 = 2 X 3

8 = 2 X 2 X 2

The greatest times 2 repeats is three times.

The greatest times 3 repeats is one time.

2 X 2 X 2 X 3 = 24

The LCM is 24, and the buses have the same leaving times every 24 minutes.

Find 24 minutes after 4:00 p.m. Change the minutes only, which are the numbers right of the colon : .

The buses will next leave together at 4:24 p.m.

5 0
3 years ago
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