Answer:
i can see the image is not there
Step-by-step explanation:
Remember that the radicand (the area under the root sign) must be positive or zero for a radical with an even index (like the square root or fourth root, for example). This is because two numbers squared or to the fourth power, etc. cannot be negative, so there are no real solutions when the radicand is negative. We must restrict the domain of the square-root function.
If the domain has already been restricted to

, we can work backwards to add 11 to both sides. We see that

must be under the radicand, so the answer is
A.
Answer:
x^3 - 3x^2 - 3x + 9 + (-36/(x+3))
OR
x^3 - 3x^2 - 3x + 9 - (36/(x+3))
Step-by-step explanation:
First set the divisor equal to 0:
x + 3 = 0
Subtract 3 from both sides
x = -3
This is what you'll divide the dividend by in synthetic division.
Take the coefficents of each term in the dividend. Do not forget the 0 placeholders:
x^4 + 0x^3 - 12x^2 + 0x -9
Coefficents: 1. 0. -12. 0 -9.
Please see the image for the next steps.
The remainder is -36. Put the remainder over the divisor and add it to the polynomial (shown in image)
-36/(x+3)
X^2 - y^2 - 2x + 6y - 8
<span>= (x^2 - 2x + 1) - (y^2 - 6y + 9) - 8 - 1 + 9 </span>
<span>= (x - 1)^2 - (y - 3)^2 </span>
<span>= [(x - 1) - (y - 3) ] [(x - 1) + (y - 3)] </span>
<span>= (x - 1 - y + 3) ( x - 1 + y - 3) </span>
<span>= (x - y + 2) (x + y - 4)</span>