<span>Let A be the center of a circle and two angles at the adjacent center AOB and BOC. Knowing the measure of the angle AOB = 120 and the measure BOC = 150, find the measures of the angles of the ABC triangle.
</span>solution
Given the above information;
AC=AB, therefore ABC is an isosceles triangle.
therefore, BAO=ABO=(180-120)/2=30
OAC=OCA=(180-90)/2=45
OBC=BCO=(180-150)/2=15
THUS;
BAC=BAO+OAC=45+30=75
ABC=OBA+CBO=15+30=45
ACB=ACO+BCO=15+45=60
Its either a or d but im not 100% positive
No, because you would have to simplify like terms. Which the simplest form would be
5x-4
Answer:
$30
Step-by-step explanation:
Okay, so we can solve this problem using fractions; $10 saved for every $15 made..
10/15=x/45
Using cross multiplication we can conclude 10*45=15x
450=15x
x=30
Hope this helps :)
51÷64= 0.796875
Round to thousandth place
0.797
