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3 years ago

What is 788.48 plus 7% rounded to the nearest cent

Mathematics

2 answers:

Softa [21]3 years ago

8 0

Answer:

$843.67

Step-by-step explanation:

788.48 x 1.07 = 843.6736

AveGali [126]3 years ago

7 0

Answer:

$843.67

Step-by-step explanation:

1% = 7.8848

7.8848 x 7 = 55.1936

788.48 + 55.1936 = 843.6736

Rounded to nearest cent = $843.67

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Write the word sentence as an equation. Then solve.<br><br> −7 increased by a number n is 12.

adell [148]

Answer:

-7n =12

n=5

Step-by-step explanation:

You said increased so that makes me think you are talking about multiplying so you would write it as -7n =12 :)

If correct, can you please mark me brainliest:)

7 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs. Find the distance between each pair of points. 5 units 4 units 2 unit

Olin [163]

Answer:

a) Distance between points A (5, 4) and B( 5, -2) is 6 units

b) Distance between points E (-2, -1) and F( -2, -5) is 4 units

c) Distance between points C (-4, 1) and D( 1, 1) is 5 units

d) Distance between points G(3, -5) and H(6, -5) is 3 units

Step-by-step explanation:

We need to find the distance between each pair

a) A (5, 4) and B( 5, -2)

the distance formula is:

$d(A,B) = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Putting values: x₁ = 5, x₂=5 and y₁= 4 and y₂= -2

$d(A,B) = \sqrt{(5-5)^2+(-2-4)^2}$

$d(A,B) = \sqrt{(0)^2+(-6)^2}$

$d(A,B) = \sqrt{36}$

$d(A,B) = 6$

Distance between points A (5, 4) and B( 5, -2) is 6 units

b) E (-2, -1) and F( -2, -5)

the distance formula is:

$d(E,F) = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Putting values: x₁ = -2, x₂=-2 and y₁= -1 and y₂= -5

$d(E,F) = \sqrt{(-2-(-2))^2+(-5-(-1))^2}$

$d(E,F) = \sqrt{(0)^2+(-4)^2}$

$d(E,F) = \sqrt{16}$

$d(E,F) = 4$

Distance between points E (-2, -1) and F( -2, -5) is 4 units

c) C (-4, 1) and D( 1, 1)

the distance formula is:

$d(C,D) = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Putting values: x₁ = -4, x₂=1 and y₁= 1 and y₂= 1

$d(C,D)= \sqrt{(1-(-4))^2+(1-(1))^2}$

$d(C,D) = \sqrt{(5)^2+(0)^2}$

$d(C,D) = \sqrt{25}$

$d(C,D) = 5$

Distance between points C (-4, 1) and D( 1, 1) is 5 units

d) G(3, -5) and H(6, -5)

the distance formula is:

$d(G,H) = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Putting values: x₁ = 3, x₂=6 and y₁= -5 and y₂= -5

$d(G,H)= \sqrt{(6-(3))^2+(-5-(-5))^2}$

$d(G,H) = \sqrt{(3)^2+(0)^2}$

$d(G,H) = \sqrt{9}$

$d(G,H) = 3$

Distance between points G(3, -5) and H(6, -5) is 3 units

8 0

3 years ago

One-eighth of the 32 students in the class went abroad for fall break. How many students went abroad?

Arada [10]

Four students went abroad.

6 0

3 years ago

Read 2 more answers

Write the grammatical sentence as an algebraic one: Nine less than half a number is twenty-four.

soldi70 [24.7K]

Answer:

x/2-9=24

Explanation:

Nine less:
-9
Half a number:
x/2
So nine less than half a number:
x/2-9
Is 24:
=24

So x/2-9=24

To solve for the number:
Add 9 to both sides:
x/2-9+9=24+9
x/2=33
Multiply both sides by 2:
2(x/2)=33(2)
x=66

8 0

3 years ago

What is the answer so I could get the question

qaws [65]

Answer:My answer is Temp-pH I

I don't know if it is right or not

6 0

3 years ago