12,000×(1+0.12÷2)^(2×6)+50,000×(1+0.12÷2)^(2×2)=87,270.21
<span>20,000 is 1/10 of 200,000. You can tell that this sentence is true by multiplying 200,000 by 1/10 which will give you the answer: 20,000.</span>
The value of the truck initially, Ao is
83000
1-0.16=0.84
1-0.26=0.74
After one year the value
Y=83,000×(0.84)=69,720
Y=83,000×(0.74)=61,420
When you compare the results you will see that the graph would fall at a faster rate to the right because the depreciation rate of 26% is higher than the depreciation rate of 16%
Hope it helps
