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dsp73
2 years ago
10

Calculate the volume needed of a stock (undiluted) solution that has a concentration of 4.2 M and is then diluted to 0.034 L of

0.66 M solution.
Chemistry
1 answer:
Mnenie [13.5K]2 years ago
5 0

M1V1 = M2V2

V1(4.2) = (0.66)(0.034)

V1 = 0.0053L

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Answer:

biosphere

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A two-liter soft drink bottle can withstand apressure of
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Explanation:

According to the ideal gas equation, PV = nRT.

where,     P = pressure,        V = volume

               n = no. of moles,      R = gas constant

               T = temperature

Also, density is equal to mass divided by volume. And, no. of moles equals mass divided by molar mass.

Therefore, then formula for ideal gas could also be as follows.

                 P = \frac{mass}{volume \times molar mass} \times RT

or,             P = \frac{density}{\text{molar mass}} \times RT

Since, density is given as 0.789 g/ml which is also equal to 789 g/L (as 1000 mL = 1 L). Hence, putting the given values into the above formula as follows.

               P = \frac{density}{\text{molar mass}} \times RT

                  = \frac{789 g/l}{46.06 g/mol} \times 0.0821 L atm/mol K \times 373 K

                  = 525 atm

As two-liter soft drink bottle can withstand a pressure of  5 atm and the value of calculated pressure is 525 atm which is much greater than 5 atm.

Therefore, the soft drink bottle will  obviously explode.

4 0
3 years ago
What is the weight of a 30.0 kg object?<br> 3.0 N<br> 300 N<br> 6.8 N<br> 132 N
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Explanation:

w \:  = mg \\  = 30\:kg \times 10\:ms^{-2}\\=300\:kg\:ms^{-2}  \\  = 300\:N

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A baseline for an experimental investigation is provided by the
Rina8888 [55]
A baseline for experimental investigation is provided by an hypothesis. This is a must before conducting experiments. Also, it is the hypothesis that is being proved by doing the experiments. So, hypothesis is very important in research studies. Hope this answers the question.
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Three isotopes of argon occur in nature – 36 18Ar, 38 18Ar, 40 18Ar. Calculate the average atomic mass of argon to two decimal p
likoan [24]

Answer: 3) 39.96 amu

Explanation:

Mass of isotope Ar- 36 = 35.97 amu

% abundance of isotope Ar- 36= 0.337% = \frac{0.337}{100}=3.37\times 10^{-3}

Mass of isotope Ar- 38 = 37.96 amu

% abundance of isotope 2 = 0.063 % = \frac{0.063}{100}=6.3\times 10^{-4}

Mass of isotope Ar- 40 = 39.96 amu

% abundance of isotope 2 = 99.600 % = \frac{99.600}{100}=0.996

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=\sum[(35.97\times 3.37\times 10^{-3})+(37.96\times 6.3\times 10^{-4})+(39.96\times 0.996)]

A=39.96amu

Therefore, the average atomic mass of argon is 39.96 amu

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