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2 years ago

A student's bank account is represented in the table shown.

Mathematics

1 answer:

melomori [17]2 years ago

8 0

The desmos link is in the reply section below...

1.) y = 1.56x + 1.29

2.) the slope is 1.56

As the weeks are increasing, the student's balance is growing about 1.56 per week.

3.) y = 24.69

4.) 50 = 1.56x + 1.29

50 - 1.29 = 1.56x + 1.29 - 1.29

48.71 =1.56x

48.71 / 1.56

31.2

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One leg of a right triangle is 16 centimeters long,and the area of the triangle is 152 square centimeters. What is the length of

denpristay [2]

$16 \times x \div 2 = 152 \\ 16 \times x = 304 \\ x = 19$

The other leg is 19.

3 0

3 years ago

Those 2 questions I need help with . find sec θ and tanθ

Zielflug [23.3K]

STEP - BY - STEP EXPLANATION

What to find?

The the value of secθ.

Given:

(4, 3)

⇒(x, y) = (4, 3)

Step 1

Draw a sketch.

Step 2

Substitute the values into the trig. ratio formula below.

$tan\theta=\frac{opposite}{adjacent}$

From the sketch above, opposite = 3 and adjacent = 4

$tan\theta=\frac{3}{4}$

Step 3

Find the value of the hypotenuse side using Pythagoras theorem.

let h be the hypotenuse side.

$\begin{gathered} h^2=4^2+3^2 \\ \\ =16+9 \\ \\ =25 \\ \\ h=5 \end{gathered}$

Hence, hypotenuse = 5

Step 4

Substitute the values into the formula below:

$\begin{gathered} cos\theta=\frac{adjacent}{hypotenuse} \\ \\ =\frac{4}{5} \end{gathered}$

But,

$sec\theta=\frac{1}{cos\theta}=\frac{1}{\frac{4}{5}}=\frac{5}{4}$

ANSWER

secθ= 5/4

tanθ=3/4

7 0

1 year ago

There are 7 gallons of black paint available to motorola. If 5/9 gallons is used each run, How many runs can we paint?

nadya68 [22]

There are 7 gallons of black paint available to motorola. If 5/9 gallons is used each run. To find the amount of runs you can paint, you have to divide the total by the amount for each run.

$7 \div \frac{5}{9}$

When dividing fractions, you have to keep, change, and flip.

$Keep\ 7 \\ Change\ \div\ to\ \times \\ Flip \frac{5}{9} = \frac{9}{5}$

Your new equation is:

$7 \times \frac{9}{5}$

Multiply:

$7 \times \frac{9}{5} = \frac{63}{5} = 12 \frac{3}{5}$

You can paint $12 \frac{3}{5}$ or $12.6$ runs.

4 0

3 years ago

Please help me with these two math problems that I do not quite understand. This is urgent!

g100num [7]

Answer:

1) $a_{n}=a_{1}+(n-1)d\Rightarrow a_{n}=-1-2(n-1)\\a_{2}=-1-2(2-1)\Rightarrow a_{2}=-3\\a_{3}=-1-2(3-1)\Rightarrow a_{3}=-5\\(...)\\a_{10}=-1-2(10-1)=-19$

2) $a_{10}=4+8(10-1)\Rightarrow a_{10}=76$

Step-by-step explanation:

1) To write an Arithmetic Sequence, as an Explicit Term, is to write a general formula to find any term for this sequence following this pattern:

$a_{n}=a_{1}+d(n-1)\Rightarrow \left\{\begin{matrix}a_{n}=n^{th}\: term\\a_1=1st \: term \\d=\: difference\\n=n^{th}\, term\end{matrix}\right.$

<em>"Write an explicit formula for each explicit formula A(n)=-1+(n-1)(-2)"</em>

This isn't quite clear. So, assuming you meant

Write an explicit formula for each term of this sequence A(n)=-1+(n-1)(-2)

As this A(n)=-1+(n-1)(-2) is already an Explicit Formula, since it is given the first term $a_{1}=-1$ the common difference $d=-2$ let's find some terms of this Sequence through this Explicit Formula:

$a_{n}=a_{1}+(n-1)d\Rightarrow a_{n}=-1-2(n-1)\\a_{2}=-1-2(2-1)\Rightarrow a_{2}=-3\\a_{3}=-1-2(3-1)\Rightarrow a_{3}=-5\\(...)\\a_{10}=-1-2(10-1)=-19$

2) $(4,12,20,28, ..)$ In this Arithmetic Sequence the common difference is 8, the first term value is 4.

Then, just plug in the first term and the common difference into the explicit formula:

$a_{10}=4+8(10-1)\Rightarrow a_{10}=76$

6 0

2 years ago

Your friend Phil, asks you what you think about a new scratch-off lottery game. It costs $10 to play this game, There are two ou

weqwewe [10]

Answer: I am going to put a link

maybe its going to help you?

Step-by-step explanation:

http://s3.amazonaws.com/illustrativemathematics/illustration_pdfs/000/001/217/original/illustrative_mathematics_1217.pdf?1390751150

7 0

2 years ago