How would you express sin(-a-b)
1 answer:
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The resultant graph is shown in the attached image.
Explanation:
Before we begin, remember that when we multiply by a negative sign, we flip the sign of the inequality
The given inequality is:
-y ≤ 3x - 5
We will multiply both sides by -1 to get a positive y vale. This will give us:
y ≥ -3x + 5
Now, to graph the inequality, we will first draw the line y = -3x + 5 and then shade the region having y values greater than the line.
To know the region, you will simply use trial and error method for random points on the two sides of the line.
The final solution would be as shown in that attachment.
Hope this helps :)
Explanation:
Before we begin, remember that when we multiply by a negative sign, we flip the sign of the inequality
The given inequality is:
-y ≤ 3x - 5
We will multiply both sides by -1 to get a positive y vale. This will give us:
y ≥ -3x + 5
Now, to graph the inequality, we will first draw the line y = -3x + 5 and then shade the region having y values greater than the line.
To know the region, you will simply use trial and error method for random points on the two sides of the line.
The final solution would be as shown in that attachment.
Hope this helps :)