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padilas [110]
2 years ago
11

5x-3=11-2x. I gotta

Mathematics
2 answers:
avanturin [10]2 years ago
8 0

Answer:

2

Step-by-step explanation:

5x - 3 = -2x + 11

    +3             +3

--------------------------

5x = -2x + 14

+2x  +2x

-------------------

7x = 14

/7     /7

--------------

X = 2

ryzh [129]2 years ago
6 0

Answer:

x = 2

Step-by-step explanation:

Add 2x from each side giving you

7x - 3 = 11

Add 3 to each side

7x = 14

Divide by 7

x = 2

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An angle's measure is equal to 24 less than its complement. Find the angle's measure.
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A complementary angle is an angle that has measurements that add up with another angle to equal 90 degrees. To find the measure of the angle you would subtract 90 degrees from the measure of the given angle. So you would subtract 90 from 24 to get 66. So the measure of the angle would be 66 degrees. Thank you

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3 years ago
One in 1000 adults is afflicted with a rare disease forwhich a diagnostic test has been developed. The test is such,that when an
mel-nik [20]

Answer:

0.0893

Step-by-step explanation:

Let A be the event that the individual has the disease

Let Aⁿ be the event that the individual doesn't have the disease

Let B be the event of a positive result showing.

Now,

We are told One in 1000 adults is afflicted with the disease.

Thus;

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P(Aⁿ) = 1 - 0.001 = 0.999

Also,we are told that when an individual has the disease, a positive result will occur 98% of the time.

Thus;

P(A|B) = 98% = 0.98

Also, we are told that an individual without the disease will show a positive result only 1% of the time. Thus;

P(Aⁿ|B) = 1% = 0.01

Now, from fundamental rule, let's find P(B). Thus;

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P(A|B) = [P(A|B) × P(A)]/P(B)

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6 0
3 years ago
Use Remainder Theorem to determine if x-2 is a factor of the polynomial f(x)=3x^5 - 7x^3 -
morpeh [17]

<u>Answer:</u>

(x - 2) is not a factor of f(x)  = 3x^5 - 7x^3 -  11x^2 + 2

<u>Step-by-step explanation:</u>

According to the Remainder Theorem, when a polynomial f(x) is divided by a term (x - r), then the remainder must be f(r).

So first we will divide f(x) by (x - 2) using long division to get:

(3x^5 - 7x^3 -  11x^2 + 2) / (x - 2)

= 3x^4 + (6x^4 - 7x^3 - 11x^2 + 2) / (x-2)

= 3x^4 + 6x^3 + (5x^3-11x^2+2) / (x - 2)

= 3x^4 + 6x^3 + 5x^2 (-x^2 + 2) / (x - 2)

= 3x^4 + 6x^3 + 5x^2 -x -2 - (2) / (x -2)

= \frac{-2 + 3x^{5} - 7x^{3} - 11x^{2} + 2x}{x - 2} - 2

Therefore the remainder is -2.

Now check x = 2 for 3x^5 - 7x^3 -  11x^2 + 2:

3(2)^5 - 7(2)^3 -  11(2)^2 + 2 = -2

The Remainder Factor theorem also states that if (x - r) is a factor of f(x) then f(r) must be 0.

So we found that f(2) = -2, therfore (x - 2) is not a factor of f(x) .


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