Question

If A= (-1,3) and B=(11,-8) what is the length of ab

Answer 1

Answer:

16.3 units ( to 1 dec. place )

Step-by-step explanation:

Using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = A(- 1, 3) and (x₂, y₂ ) = B(11, - 8)

AB = $\sqrt{(11+1)^2+(-8-3)^2}$

     = $\sqrt{12^2+(-11)^2}$

     = $\sqrt{144+121}$

     = $\sqrt{265}$ ≈ 16.3 ( to 1 dec. place )