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goldenfox [79]
4 years ago
5

If A= (-1,3) and B=(11,-8) what is the length of ab

Mathematics
1 answer:
maks197457 [2]4 years ago
8 0

Answer:

16.3 units ( to 1 dec. place )

Step-by-step explanation:

Using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = A(- 1, 3) and (x₂, y₂ ) = B(11, - 8)

AB = \sqrt{(11+1)^2+(-8-3)^2}

     = \sqrt{12^2+(-11)^2}

     = \sqrt{144+121}

     = \sqrt{265} ≈ 16.3 ( to 1 dec. place )

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Solve for kkk. \dfrac{k}4+ 3= 14 4 k ​ +3=14
masha68 [24]

Answer: k=1

Step-by-step explanation:

Simplify   1/k

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2.2       Adding up the two equivalent fractions

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Simplify 3/k

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 3                      (1 - 2k)

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        2     2 • k

   2 =  —  =  —————

        1       k  

7.1   Subtracting a whole from a fraction

3 + 2 • k     2k + 3

—————————  =  ——————

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8.1       Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

        2     2 • k

   2 =  —  =  —————

        1       k  

9.1     Pull out like factors :

  2 - 2k  =   -2 • (k - 1)

10.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

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The equation now takes the shape :

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Equations which are never true:

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