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goldenfox [79]
3 years ago
5

If A= (-1,3) and B=(11,-8) what is the length of ab

Mathematics
1 answer:
maks197457 [2]3 years ago
8 0

Answer:

16.3 units ( to 1 dec. place )

Step-by-step explanation:

Using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = A(- 1, 3) and (x₂, y₂ ) = B(11, - 8)

AB = \sqrt{(11+1)^2+(-8-3)^2}

     = \sqrt{12^2+(-11)^2}

     = \sqrt{144+121}

     = \sqrt{265} ≈ 16.3 ( to 1 dec. place )

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