All categories

2 years ago

PLZ HELP!!!!!!!!

Mathematics

2 answers:

nekit [7.7K]2 years ago

8 0

Answer:

B. Function 2

Step-by-step explanation:

Line P gradient is

Gradient = rise/run

= 1/4

Negative slope so gradient is - 1/4

Out of all the gradient, the lowest value has to be function 2 or line p & not 1/4r-5 because when r is 1 we get a gradient of 1.

-1/4xr - 5

-1/4x1 - 5

-1/4-5

-1/-1 = 1

Plus, 1 is greater than - 1/4 or - 0.25.

11Alexandr11 [23.1K]2 years ago

6 0

Answer:

Function 1

Step-by-step explanation:

I got it correct on khan academy

You might be interested in

A dartboard consists of two concentric circles. The probability of hitting the inner circle is

stepan [7]

Given:
Diameter of outer circle = 20 inches.

We need to find the Area of the outer circle to get the radius of the inner circle.

Area = πr²

Outer circle Area = 3.14 * (10in)² = 314 in²

314 in² * 64% probability = 200.96 in² Area of the inner circle.

200.96 in² = 3.14 * r²
200.96 in² / 3.14 = r²
64 in² = r²
√64 in² = √r²
8 in = r

radius of inner circle is 8 inches.

3 0

3 years ago

ANSWER THIS QUESTION FOR BRAINLEST AND 10 POINTS

weqwewe [10]

Answer: third dot

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Find a factor of 3x^2- 16x - 12

Greeley [361]

Answer:

x= -2/3 and 6

Step-by-step explanation:

3x²-16x-12

3x²-18x+2x-12

(3x²-18x)+(2x-12)

3x(x-6)+2(x-6)

(3x+2)(x-6)

x= -2/3 and 6

8 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Cint%20t%5E2%2B1%20%5C%20dt" id="TexFormula1" title="\frac{d}{dx} \

Kisachek [45]

Answer:

$\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2} t^2+1 \ \text{dt} \ = \ 2x^5-8x^2+2x-2$

Step-by-step explanation:

$\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2} t^2+1 \ \text{dt} = \ ?$

We can use Part I of the Fundamental Theorem of Calculus:

$\displaystyle\frac{d}{dx} \int\limits^x_a \text{f(t) dt = f(x)}$

Since we have two functions as the limits of integration, we can use one of the properties of integrals; the additivity rule.

The Additivity Rule for Integrals states that:

$\displaystyle\int\limits^b_a \text{f(t) dt} + \int\limits^c_b \text{f(t) dt} = \int\limits^c_a \text{f(t) dt}$

We can use this backward and break the integral into two parts. We can use any number for "b", but I will use 0 since it tends to make calculations simpler.

$\displaystyle \frac{d}{dx} \int\limits^0_{2x} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}$

We want the variable to be the top limit of integration, so we can use the Order of Integration Rule to rewrite this.

The Order of Integration Rule states that:

$\displaystyle\int\limits^b_a \text{f(t) dt}\ = -\int\limits^a_b \text{f(t) dt}$

We can use this rule to our advantage by flipping the limits of integration on the first integral and adding a negative sign.

$\displaystyle \frac{d}{dx} -\int\limits^{2x}_{0} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}$

Now we can take the derivative of the integrals by using the Fundamental Theorem of Calculus.

When taking the derivative of an integral, we can follow this notation:

$\displaystyle \frac{d}{dx} \int\limits^u_a \text{f(t) dt} = \text{f(u)} \cdot \frac{d}{dx} [u]$
where u represents any function other than a variable

For the first term, replace $\text{t}$ with $2x$ , and apply the chain rule to the function. Do the same for the second term; replace

$\displaystyle-[(2x)^2+1] \cdot (2) \ + \ [(x^2)^2 + 1] \cdot (2x)$

Simplify the expression by distributing $2$ and $2x$ inside their respective parentheses.

$[-(8x^2 +2)] + (2x^5 + 2x)$
$-8x^2 -2 + 2x^5 + 2x$

Rearrange the terms to be in order from the highest degree to the lowest degree.

$\displaystyle2x^5-8x^2+2x-2$

This is the derivative of the given integral, and thus the solution to the problem.

6 0

2 years ago

How to rename 71 thousand=

Travka [436]

You can do this: 71,000 or 71,000/1

3 0

2 years ago