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Valentin [98]
3 years ago
8

Brandon picked 14 of a pound of cherries. That afternoon, Brandon's brother ate 12 of the cherries. How many pounds of cherries

did Brandon's brother eat? Group of answer choices
Mathematics
1 answer:
stellarik [79]3 years ago
8 0

Answer:

2

Step-by-step explanation:

Brandon picked 14 pounds of cherries but later in the afternoon Brandon's brother ate 12 so you would subtracts

14-12 = 2

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Express tan F as a fraction in simplest terms
gladu [14]

Answer:

  5/12

Step-by-step explanation:

You want the tangent of angle F in right triangle FGH with sides FG=24, GH=10, and FH=26.

<h3>Tangent</h3>

The mnemonic SOH CAH TOA is intended to remind you of the relations between trig functions and the sides of a right triangle. The TOA part of this tells you ...

  Tangent = Opposite/Adjacent

<h3>Application</h3>

The side opposite angle F is GH = 10.

The side adjacent to angle F is FG = 24.

Then the tangent is ...

  tan(F) = GH/FG = 10/24

  tan(F) = 5/12 . . . . . reduced to lowest terms

3 0
1 year ago
Is this an example of a horizontal asymptote?
8_murik_8 [283]

Answer:

Step-by-step explanation:

Hi there,

The graph indicated is showing a horizontal asymptote. In fact, it is showing both a horizontal and a <em>vertical </em>asymptote.

To tell which type it is, notice where the graph "shoots off" and almost forms an imaginary straight line in one direction. Using this logic, the horizontal asymptote will be exactly horizontal, parallel to x-axis, and vertical asymptote will be exactly vertical, parallel to y-axis.

With this graph, we notice the horizontal asymptote is at y=0, where the x-axis is. The vertical asymptote is bit more difficult to determine graphically, but can definitely say it is past x=-10. We could determine it if we had the function, but that is not necessary for this question.

Study well, and persevere. If you liked this solution, leave a Thanks or give a rating!

thanks,

6 0
3 years ago
The width of a rectangular painting is 5 inches shorter than it's length. Creat a table of values to include possible widths,len
Misha Larkins [42]
A = L * W
W = L - 5

                                these are in inches...
               length                width                 area
                  10                      5                       50 in^2
                  9                        4                       36   "
                  8                        3                       24   "
                  7                        2                       14   "
                  6                        1                        6    "
                 
6 0
3 years ago
A cable television compan is laying cable in an area with underground utilities. Two subdivisions are located on opposite sides
Schach [20]

Answer:

Step-by-step explanation:

Given:

Point Q = Q is on the north bank 1200 m east of P $40/m to lay cable underground and $80/m way to lay the cable.

Lets denote T be a point on north bank, therefore, point T is t m east and 100m north of P.

Note that 0 < t < 1200

Distance from P to T using Pythagoras theorem:

PT^2 = PQ^2 + QT^2

PT = √(t²+100²) = √(t²+10,000)

Distance from T to Q:

TQ = 1200 - t

From above, Cable from P to T is underwater, and costs $80/m to lay.

Cable from T to Q is underground, and costs $40/m to lay.

Total cost of the cable:

C(t) = 80√(t²+10,000) + 40(1200 - t)

Cost is at its minimum: when dC/dt = C'(t) = 0 and d^2C/dt^2 = C''(t) > 0

dC/dt = C'(t)

= 80 * 1/2 (t² + 10,000)^(-1/2) × 2t + 40 × (-1)

dC/dt = C'(t)

= 80t/√(t² + 10,000) - 40 = 0

80t/√(t² + 10,000) = 40

80t = 40√(t² + 10,000)

2t = √(t² + 10,000)

square both sides:

4t² = t² + 10,000

3t² = 10,000

t² = 10,000/3

t = 100/√3

≈ 57.735

d^2C/dt^2 =

C''(t) = [80√(t² + 10,000) - 80t × t/√(t²+10,000)] /√(t²+10,000)

C''(t) = [(80(t²+10,000) - 80t²) / √(t²+10,000)] /√(t²+10,000)

C''(t) = 800,000 / (t² + 10,000)^(3/2)

C''(t) > 0 for all t

Therefore C(t) is minimized at t = 100/√3

C(100/√3) = 80√(10,000/3 + 10,000) + 40 × (1200 - 100/√3)

= 80 √(40,000/3) + 48,000 - 4000/√3

= 16000/√3 + 48,000 - 4000/√3

= 48,000 + 12,000/√3

= 48,000 + 4,000√3

= 4000 (12 + √3)

≈ 54,928.20

Minimum cost is $54,928.20

This occurs when cable is laid underwater from point P to point T(57.735 m east and 100m north of P) and then underground from point T to point Q (1200 - 57.735)

= 1142.265 m

5 0
3 years ago
Z is twelve less than the sum of x and y
Furkat [3]
X+y-12=z
EXPLANATION:
7 0
3 years ago
Read 2 more answers
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