May has a square garden with an area of 65 square feet. What is the

Mathematics

1 answer:

madam [21]3 years ago

6 0

Answer:

1.625 Feet

Step-by-step explanation:

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2.Solve the system using substitution.

Lena [83]

2x+2y=38
y=x+3

First you would substitute the y for x+3
2x+2(x+3)=38

You would multiply the 2 by the x+3
2x+2x+6=38

Add the 2x and the 2x
4x+6=38

Subtract the 6 on both sides
4x=32

Divide the 4 on both sides
x=8

Now substitute the x in the second problum for 8
y=8+3

Add the 8 and the 3 to solve for y
y=11

Your answers
x=8
y=11
the correct answer would be A:(8,11)

3 0

3 years ago

What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)

zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

Integrals
Definite Integrals
Integration Constant C

Arc Length Formula [Parametric]: $\displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.$

Interval [0, π]

Step 2: Find Arc Length

[Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]: $\displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.$
Substitute in variables [Arc Length Formula - Parametric]: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx$
[Integrand] Simplify: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx$
[Integral] Evaluate: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}$