All categories

1 year ago

Can someone plz help me? :(

Chemistry

1 answer:

Tju [1.3M]1 year ago

8 0

Answer:

the Respiratory System and Circulatory system

Explanation:

You might be interested in

You have added IgG-sensitized red cells to the negative indirect antiglobulin test result of the antibody screen procedure. You

Ivanshal [37]

Answer:

Positive

Explanation:

The antibody screen interpretation is positive. That's because of clump formation when antibody reacts with the antigen and agglutination occurs.

It means that the antibodies were present in the sample that react with the antigen present in the test tube.

5 0

3 years ago

Earth's atmosphere, which traps heat and radiation from the sun, helps to keep our temperature somewhat stable, even when we are

Elis [28]

Answer:

It is true

Explanation:

6 0

3 years ago

Read 2 more answers

The useful metal manganese can be extracted from the mineral rhodochrosite by a two-step process.... In the first step, manganes

frez [133]

Answer : The mass of $MnCO_3$ required are, 35 kg

Explanation :

First we have to calculate the mass of $MnO_2$ .

The first step balanced chemical reaction is:

$2MnCO_3+O_2\rightarrow 2MnO_2+2CO_2$

Molar mass of $MnCO_3$ = 115 g/mole

Molar mass of $MnO_2$ = 87 g/mole

Let the mass of $MnCO_3$ be, 'x' grams.

From the balanced reaction, we conclude that

As, $(2\times 115)g$ of $MnCO_3$ react to give $(2\times 87)g$ of $MnO_2$

So, $xg$ of $MnCO_3$ react to give $\frac{(2\times 87)g}{(2\times 115)g}\times x=0.757xg$ of $MnO_2$

And as we are given that the yield produced from the first step is, 65 % that means,

$60\% \text{ of }0.757xg=\frac{60}{100}\times 0.757x=0.4542xg$

The mass of $MnO_2$ obtained = 0.4542x g

Now we have to calculate the mass of $Mn$ .

The second step balanced chemical reaction is:

$3MnO_2+4Al\rightarrow 3Mn+2Al_2O_3$

Molar mass of $MnO_2$ = 87 g/mole

Molar mass of $Mn$ = 55 g/mole

From the balanced reaction, we conclude that

As, $(3\times 87)g$ of $MnO_2$ react to give $(3\times 55)g$ of $Mn$

So, $0.4542xg$ of $MnO_2$ react to give $\frac{(3\times 55)g}{(3\times 87)g}\times 0.4542x=0.287xg$ of $Mn$

And as we are given that the yield produced from the second step is, 80 % that means,

$80\% \text{ of }0.287xg=\frac{80}{100}\times 0.287x=0.2296xg$

The mass of $Mn$ obtained = 0.2296x g

The given mass of Mn = 8.0 kg = 8000 g (1 kg = 1000 g)

So, 0.2296x = 8000

x = 34843.20 g = 34.84 kg = 35 kg

Therefore, the mass of $MnCO_3$ required are, 35 kg

4 0

2 years ago

Read 2 more answers

Does anyone know the answer?

valentina_108 [34]

An artery carries blood away from the heart, a vein carries blood to the heart.

3 0

2 years ago

Explain how glucose and starch are related

weeeeeb [17]

Answer:

Starch is the stored form of sugars in plants and is made up of a mixture of amylose and amylopectin (both polymers of glucose). ... The cells can then absorb the glucose. Starch is made up of glucose monomers that are joined by α 1-4 or α 1-6 glycosidic bonds.

Explanation:hope that helps you lots

4 0

2 years ago