Solution:[tex]Let the molar mass of metal M is 'a',\\
\rn(so)\\
\frac{M_{o}}{2M_{H}+2M_{o}+a} =\frac{2.16}{2.1+2.16+a} =0.328\\
By simple algebric calculation. We get,\\ a=63.56g/mol\\
\rn(Now,)\\
We have to confirm which metal has the molar mass of 63.56g/mol. By using periodic table we have to find it the we get it is Copper(Cu).
Group 7
Explanation:
The unknown element belongs to the seventh group on the periodic table of elements.
Ionic bonds are usually formed between metals and nonmetals. They formed by the transfer of electrons from the less electronegative specie to the more electronegative one.
The metals usually lose electron because they are highly electropositive species.
- If we have a magnesium atom with two valence electrons.
- To form ionic bonds, it must transfer the two electrons to another atom.
- The other atom, a nonmetal must be ready to accommodate and receive the donated electrons.
- This ensure that its own octet is complete.
- Group 6 elements requires 2 electrons to have a complete octet.
- They can receive the two electrons
But we were told that there are two atoms of that element for each of the magnesium atom;
the atom must have a capacity of collecting one electron each to be stable.
Such atoms are found in Group 7 on the periodic table.
learn more:
Ionic bond brainly.com/question/6071838
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Answer:
0.767 moles of ammonium phosphate are produced
Explanation:
The reaction of ammona (NH3), with phosphoric acid is:
3 NH3 + H3PO4 → (NH4)3PO4
<em>Where 3 moles of ammonia reacts per mole of H3PO4 to produce 1 mole of ammonium phosphate.</em>
<em />
If 2.3 moles of ammonia reacts, the moles of ammonium phosphate produced if phosphoric acid is in excess are:
2.3 moles NH3 * (1 mole (NH4)3PO4 / 3 moles NH3) =
<h3>0.767 moles of ammonium phosphate are produced</h3>
<em />
Answer:
c = 5505263.16 J/g.°C
Explanation:
Given data:
Mass of ring = 12 mg (12/1000 = 0.012 g)
Calories used = 30.0 cal (30.0 ×4184 = 125520 J)
Temperature increases = 1.9°C
Specific heat of ring = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
125520 J = 0.012 g×c ×1.9°C
125520 J = 0.0228 g.°C ×c
c = 125520 J / 0.0228 g.°C
c = 5505263.16 J/g.°C
