Answer:
2.1 atm
Explanation:
We are given the following variables to work with:
Initial pressure (P1): 2.5 atm
Initial temperature (T1): 320 K
Final temperature (T2): 273 K
Constant volume: 7.0 L
We are asked to find the final pressure (P2). Since volume is constant, we want to choose a gas law equation that relates initial pressure and temperature to final pressure and temperature. Gay-Lussac's law does this:
We can rearrange the law algebraically to solve for 
.
Substitute your known variables and solve:
The level in the beaker will increase because the volumes of the spheres will also be added to the volume of the water. First, we must determine the volume of each sphere. For this, we will use:
density = mass / volume
We can check the density of both aluminum and iron in literature, and given the mass, we may obtain the volume.
Aluminum:
Density = 2.70 g/ml
Mass = 20.4 g
Volume = 20.4 / 2.7 = 7.56 ml
Iron:
Density = 7.87 g/ml
Mass = 49.4 g
Volume = 49.4 / 7.87 = 6.28 ml
Now, we add these volumes to the volume of water present:
75.2 + 6.28 + 7.56 = 89.04
The new level will be 89.0 ml
Answer:
Density = 8.75ml
Explanation:
Density = Mass / Volume
In this problem ...
Mass = 28 grams
Volume = 31.4ml - 28.2ml = 32ml (water displacement also)
∴Density = mass /volume = 28g/32ml = 8.75g/ml
It is a constant-volume type calorimeter that measures the heat of a particular reaction or measures the calorific value of the fuels. Bomb calorimeters are built in such a way that they can withstand the large pressure produced within the calorimeter due to the reaction or burning of fuel.
Answer: Solids
Explanation:
Solids have a definite volume and structure. These are comprised of atoms, ions, and molecules closely packed together giving a confined structure to the solids. The particles are bound with strong force of attraction. The particles in the solid are arranged in an repeated, orderly, and three dimensional pattern. Depending upon the substance of the solid the particles within the solid can be ions, atoms, and can be molecules.
