Answer:17.955atm
Explanation:Pv=nrt
P= nrt/v
P= 7.25*0.08205*360/11.90
P= 214.1505/11.90
P=17.995atm
in order to determine empirical formula we have to determine the mole ratio of the given elements
Let the total mass of the compound is 100g
as given that the compound has 40% sulfur , so mass of sulfur = 40g
as given that the compound has 60% oxygen, so mass of oxygen = 60g
let us calculate the moles of each element
Moles of sulfur = mass / atomic mass = 40 / 32 = 1.25
moles of oxygen = mass / atomic mass = 60/ 16 = 3.75
In order to get simple ratio of moles we will divide both the moles with least number of moles which is 1.25
moles of sulfur = 1.25 / 1.25 = 1
moles of oxygen = 3.75 /1.25 = 3
So empirical formula will be SO₃
Given the fact that we are seeing a rise in the temperature of the globe, the artic animals in that ecosystem must adapt by a reduction in the rate of metabolism.
<h3>What is global warming?</h3>
Several evidences continue to emerge that the temperature of the earth have continued to increase and this is largely due to the fact that since the turn of the twentieth century and the rise of industrialization, there have been a rise in the emission of the carbon dioxide and other green house gases into the environment. As a result of this, the temperature of the earth has continued to rise steadily leading to the melting of the ice cover and the destruction of ecosystems that are found around the artic regions of the earth.
Now, we know that an organism is able to adapt to the changes that occur in its habitat by being able to alter some of its structure and function.
Given that the organisms that live in the artic are adapted to cold regions and low temperatures, the metabolic rate of the organisms is high in order to produce heat.
As a result of the rise in global temperatures, the organisms would have to reduce their rate of metabolism.
Learn more about global warming:brainly.com/question/12908180
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Answer:
42.6 % CHCl₃, 13.83 % C₃H₆O and 43.5 % CH₃COBr
Explanation:
This is a solution with 3 compounds:
96.2 g of CHCl₃
31.2 g of C₃H₆O
98.1 g of CH₃COBr
Total mass of solution is : 96.2g + 31.2 g + 98.1g = 225.5 g
Percent by mass is, the mass of the compounds in 100 g of solution
Let's prepare the rule of three
225.5 g of solution have ____ 96.2 g ___ 31.2 g _____98.1 g
100 g of solution would have ____
(100 . 96.2) / 225.5 = 42.6
(100 . 31.2) / 225.5 = 13.83
(100 . 98.1) / 225.5 = 43.5
