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eduard
3 years ago
14

A student takes a measured volume of 3.00 M HCl to prepare a 50.0 mL sample of 1.80 M HCl. What volume of 3.00 M HCl did the stu

dent use to make the sample? Use mc020-1.jpg. 3.70 mL 16.7 mL 30.0 mL 83.3 mL
Chemistry
2 answers:
ivann1987 [24]3 years ago
7 0
Um in  not sure but i think is=t should be 60.2874

Yuliya22 [10]3 years ago
7 0
Use the dilution formula C1V1= C2V2

C1= 3.0 M
V1= ??
C2= 1.80 M
V2= 50.0mL

(3.0 M) x (V1)= (1.80 M) x (50.0 mL)

V1= 30.0 mL. 
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Answer:

D. 40 % increase  

Step-by-step explanation:

r = k[A]²/[B]

The rate is inversely proportional to [B]. If [B] is doubled, the rate is halved.

We must double this rate to get back to the original.

The rate is directly proportional to [A]².

2 = [A]₂/[A]₁²     Take the square root of each side

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3 years ago
What Happens When extra Solute is added to unsaturated ,saturated and supersaturated solution​
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2 years ago
A sailor on a trans-Pacific solo voyage notices one day that if he puts 375. mL of fresh water into a plastic cup fresh water we
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Answer:

Amount of salt dissolved in each liter of seawater = 40 g

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According to Archimedes principle, a body will float in a fluid if the upthrust experienced by a body is equal to the to the weight of the body.

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From the above principle, since the freshwater and cup floats in the seawater, their combined weight equals the upthrust.

Therefore, mass of equal volume of displaced seawater = mass of freshwater + mass of cup

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mass of salt in 375 mL seawater = mass of seawater - mass of freshwater

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Since 15 g of salt are dissolved in 375 mL seawater, mass of salt in 1 L of seawater =(1000 mL/ 375) * 15g = 40 g

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3 years ago
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3 years ago
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Answer:

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Explanation:

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