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Anit [1.1K]
2 years ago
14

I need to understand the steps and why. ty.

rt{y} ^4" alt="\sqrt{y} ^4" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
e-lub [12.9K]2 years ago
8 0

Answer:  y^2

Reason:

A square root represents an exponent of 1/2

So \sqrt{y} = y^{1/2}

Raising that to the fourth power gets us this,

(\sqrt{y})^4 = (y^{1/2})^4\\\\
(\sqrt{y})^4 = y^{(1/2)*4}\\\\
(\sqrt{y})^4 = y^{2}\\\\

----------------

Edit: Here's an alternative route

(\sqrt{y})^4 = (\sqrt{y})*(\sqrt{y})*(\sqrt{y})*(\sqrt{y})\\\\
(\sqrt{y})^4 = (\sqrt{y})^2*(\sqrt{y})^2\\\\
(\sqrt{y})^4 = y*y\\\\
(\sqrt{y})^4 = y^2\\\\

The first line is possible because raising anything to the 4th power is the same as having 4 copies of it multiplied out (eg: 3^4 = 3*3*3*3 = 81).

Then in the second line, I collected the terms into pairs

By line 3, the square root and squaring exponent cancel each other out. This only works if y is not negative.

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f(0) = 6  → ANSWER

*Remember that f(0) = m(0) + n = n

If we have f(x) = mx + n, then:

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