Kelly bought a dog leash for $15.75 and a water bowl for

Mathematics

1 answer:

Step2247 [10]2 years ago

6 0

Answer: $21.94

Step-by-step explanation:

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(5s-6)(3s+2) please just give me the answer I have to turn it in today

alexandr1967 [171]

Answer:

The answer is -2

Step-by-step explanation:

you subtract common numbers, so:

5s - 3s = 2s

Then,

-6 + 2 = -4

You would then get

2s - 4

divide -4 by 2 which is -2

and your answer is s = -2

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3 years ago

The problem is in the pic

Otrada [13]

Answer:

Step-by-step explanation:

The solutions are at (-2,0) and (1,-3)

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1 year ago

Read 2 more answers

Suppose that the probability that any particle emitted by a radioactive material will penetrate a certain shield is 0.01. If 10

AnnyKZ [126]

Answer:

a)P=0.42

b) $n\geq 297$

Step-by-step explanation:

We have a binomial distribution, since the result of each experiment admits only two categories (success and failure) and the value of both possibilities is constant in all experiments. The probability of getting k successes in n trials is given by:

$P=\begin{pmatrix}n\\ k\end{pmatrix} p^k(1-p)^{n-k}=\frac{n!}{k!(n!-k!)}p^k(1-p)^{n-k}$

a) we have k=2, n=10 and p=0.01:

$P=\frac{10!}{2!(10!-2!)}0.01^2(1-0.01)^{10-2}\\P=\frac{10!}{2!*8!}0.01^2(0.99)^{8}\\P=45*0.01^2(0.99)^8=0.42$

b) We have, $1-(1-p)^n=P$ , Here P is the probability that at least one particle will penetrate the shield, this probabity has to be equal or greater than 0.95. Therefore, this will be equal to subtract from the total probability, the probability that the particles do not penetrate raised to the total number of particles.