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Mila [183]
3 years ago
15

(Score for Question 4: Click or tap here to enter text of 4 points)

Physics
1 answer:
astra-53 [7]3 years ago
7 0

The time of motion of the ball from the vertical height is independent of the horizontal velocity.

Horizontal moving projectiles is not affected by gravity and the initial velocity is equal to the final velocity.

The time of motion of ball dropped from a vertical height is calculated as follows;

h = v_0_yt \ + \ \frac{1}{2} gt^2\\\\

where;

  • <em>h </em><em>is the vertical height</em>
  • <em>t </em><em>is the </em><em>time </em><em>of motion</em>
  • <em>g </em><em>is acceleration due to gravity</em>
  • <em />v_0_y<em> is the initial </em><em>vertical velocity</em>

From the equation above, we can conclude that time of motion of the ball from the vertical height is independent of the horizontal velocity.

If there is variation in drop time, it could be as a result of applied force when the ball is dropped. This applied force influences the initial velocity which in turn alters the drop time.

Generally, horizontal moving projectiles is not affected by gravity and the initial velocity is equal to the final velocity.

Learn more about horizontal and vertical velocity here: brainly.com/question/14354319

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The awnser is A and B
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The comet-hunting astronomer who made a list of over 100 nebulae and galaxies that could be mistaken for comets was Group of ans
Keith_Richards [23]

An Astronomer who made a list of 100 nebulae and galaxies that could

be mistaken for comets was Charles Messer's.

Charles Messier's was a very famous scientist in the field of Astronomy.

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5 0
2 years ago
You push against a steamer trunk with a force of 750 N at an angle of 25° with the horizontal . The trunk is on a flat floor and
djverab [1.8K]
This means that the horizontal force is 750sin(25°). To be able to move the truck, force applied must be greater than static friction, which equals to its coefficient (0.77) x normal contact force (= weight)

Hence, 750sin(25°) = 0.77mg. m = 750sin(25°)/(0.77g)
3 0
3 years ago
1-¿Que tipo de energía usa en su hogar para el alumbrado , la calefacción y artículos de entretenían, entre otros ? 2-¿ de que m
Harman [31]

Answer:

Explanation:

1.-Energía eléctrica ( electricidad ) proveniente de una fuente AC ( es decir de corriente alterna)

2.-Hay un proveedor de servicios que lleva la energía a las comunidades en general y en particular la lleva hasta mi casa y escuela. Se define como acometida eléctrica, la infraestructura que lleva la energía desde la red de distribución al tablero principal en el abonado. La acometida puede ser aérea o subterránea, y normalmente consta de tres conductores ( de los cuales dos son calibre AWG # 8 ( dos fases ) y uno AWG # 10 ( neutro ). Esta configuración permite tener: 120 y 240 (V) en servicio en la casa y suficiente capacidad para la carga eléctrica de una casa normal

3.-Si, el tipo de corriente. En el caso de una linterna se usan "pilas" o baterías de corriente directa ( que no varia en el tiempo), en la casa la corriente es alterna de 60 ciclos por segundo de frecuencia.

4.-Si el voltaje es menor en una medida importante la ampolleta no alumbra por cuanto si por ejemplo el voltaje nominal ( o de funcionamiento es 120 V y el voltaje suministrado es 50 V ese voltaje será insuficiente para hacer funcionar el circuito). Si el voltaje es mayor dígamos 240 V la ampolleta se quema.

5.-El interruptor nos asegura la maniobra a nuestra voluntad del circuito del cual forma parte. Es decir si tengo un circuito de alumbrado ( 1 bombillo y un interruptor ) ese interruptor me permitirá apagar y encender la luz cuando yo quiera.

Los breaker son "interruptores" son dispositivos de protección para caso de sobrecargas y/o cortocircuitos

5 0
3 years ago
2. Can you place three forces of 5g, 6g, and 12g so they are in equilibrium. Justify your answer.
Bond [772]

Answer:

We cannot place three forces of 5g, 6g, and 12g in equilibrium.

Explanation:

Equilibrium means their sum must be zero.

Here the forces are 5g, 6g, and 12g.

For number of forces to be in equilibrium the magnitude of largest vector should be less than sum of the magnitude of other vectors.

Here

        Magnitude of largest force = 12 g

        Sum of magnitudes of other forces = 5g + 6g = 11g

       Magnitude of largest force >   Sum of magnitudes of other forces

So this forces cannot form equilibrium.

We cannot place three forces of 5g, 6g, and 12g in equilibrium.

4 0
3 years ago
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