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Mila [183]
2 years ago
15

(Score for Question 4: Click or tap here to enter text of 4 points)

Physics
1 answer:
astra-53 [7]2 years ago
7 0

The time of motion of the ball from the vertical height is independent of the horizontal velocity.

Horizontal moving projectiles is not affected by gravity and the initial velocity is equal to the final velocity.

The time of motion of ball dropped from a vertical height is calculated as follows;

h = v_0_yt \ + \ \frac{1}{2} gt^2\\\\

where;

  • <em>h </em><em>is the vertical height</em>
  • <em>t </em><em>is the </em><em>time </em><em>of motion</em>
  • <em>g </em><em>is acceleration due to gravity</em>
  • <em />v_0_y<em> is the initial </em><em>vertical velocity</em>

From the equation above, we can conclude that time of motion of the ball from the vertical height is independent of the horizontal velocity.

If there is variation in drop time, it could be as a result of applied force when the ball is dropped. This applied force influences the initial velocity which in turn alters the drop time.

Generally, horizontal moving projectiles is not affected by gravity and the initial velocity is equal to the final velocity.

Learn more about horizontal and vertical velocity here: brainly.com/question/14354319

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How are the magnetic domains of a magnet different from the domains of an ordinary piece of metal?
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Answer:

In a magnet, the domains all point in the same direction; in an ordinary piece of metal, they're all jumbled up.

Explanation:

In a magnet, the domains all point toward the north pole; in an ordinary piece of metal, they all point to the south pole.



Side note:
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A person wearing rollerblades starts from rest and accelerates at a constant rate. She reaches a speed of 13 mph (5.18 m/s) exac
kvv77 [185]

Answer: a. ) What is the magnitude of their average acceleration (in m/s2)

5 0
3 years ago
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Jennifer runs 5 miles east, then stops to take a break. after her break, she continues running 4 more miles east. what is her di
andreev551 [17]

Jennifer runs 5 miles east, then stops to take a break. after her break, she continues running 4 more miles east.

In this the total distance she covers is 9 miles and the total displacement is also the same as the distance that is 9 miles.

<h3>What is the difference between distance and displacement?</h3>

Displacement is the shortest distance between initial and final position, or we can say it is the straight-line distance between initial and final position.

Whereas distance is considered as the total path length covered from initial position till the final position. The Displacement of a body is always less than or equal to the distance.

Displacement can be zero in case the initial and final positions coincide, but distance can never be zero.

To know more about distance and displacement, visit:

brainly.com/question/3243551

#SPJ4

7 0
2 years ago
Explain how airplane wings and the wings of birds affect the air flowing over them to produce lift
d1i1m1o1n [39]
Because the air in their wings helps them fly
6 0
3 years ago
Synchronous communications satellites are placed in a circular orbit that is 3.59 107 m above the surface of the earth. What is
suter [353]

Answer: 0.223 m/s^{2}

Explanation:

We can solve this with the Law of Universal Gravitation and knowing the acceleration due gravity g of an object above the surface of the planet decreases with the distance (height) of this object from the center of the planet.

Well, according to the law of universal gravitation:

F=G\frac{m_{E}m}{r^2}  (1)

Where:

F is the module of the force exerted between both bodies

G=6.67(10)^{-11}\frac{m^{3}}{kgs^{2}} is the gravitational constant

m_{E}=5.98(10)^{24} kg is the mass of the Earth

m are the mass of each communications satellite

r=R_{E}+h is the distance between the center of the Earth and the satellite

R_{E}=6.38(10)^{6} m is the radius of the Earth

h=3.59(10)^{7} m is the height of the satellite, measured from the Earth's surface

On the other hand, we know according to <u>Newton's 2nd law of motion:</u>

F=mg  (2)

Combining (1) and (2):

G\frac{m_{E}m}{r^2}=mg  (3)

Isolating g:

g=\frac{G M_{E}}{r^2}  (4)

Remembering r=R_{E}+h:

g=\frac{G M_{E}}{(R_{E}+h)^2}  (5)

g=\frac{(6.67(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.98(10)^{24} kg)}{(6.38(10)^{6} m+3.59(10)^{7} m)^2}  

Finally:

g=0.223 m/s^{2}  

5 0
3 years ago
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