1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lisa [10]
3 years ago
7

a woman weighing 500 N glides across some ice, starting her glide with a speed of 4.00 m/s. if the coefficient of friction betwe

en the skates and the ice is 0.115. how far does she go before coming to rest?
Physics
1 answer:
Alex787 [66]3 years ago
4 0

Answer:

7.1 meters

Explanation:

We need to apply Newton's second law which explains the dynamics of objects under the effect of net forces.

The woman described in the question weighs 500N and has a speed of 4 m/s. If the net force acting on her was zero, she would continue to move at that speed forever (Newton's first law). But we know that there is friction and that force always goes against the movement. In the absence of a counterforce, the friction force is unbalanced and the woman will eventually stop.

The weight of the woman is

W=m.g

We can know her mass

m=\frac{W}{g}=\frac{500}{9.8}=51.02\ Kg

We know that the friction force is

F_r=\mu N

Where N is the normal force, which in this conditions is equal to the weight. So the net force is

F_{net}=-\mu W=-0.115 (500Nw)=-57.5 Nw

It's negative because it's oppossed to the movement, assumed to the right side. Since

F_{net}=m.a

a=\frac{F_{net}}{m}=\frac{-57.5}{51.02}=-1.127\ m/sec^2

From the formulas of cinematics we know:

v_f^2=v_o^2+2ax

Solving for x when v_f=0

x=-\frac{v_o^2}{2a}=-\frac{4^2}{2(-1.127)}

x=7.1\ meters

You might be interested in
Tarik winds a small paper tube uniformly with 183 turns 183 turns of thin wire to form a solenoid. The tube's diameter is 9.49 m
Rufina [12.5K]
<h2>Answer:</h2>

143μH

<h2>Explanation:</h2>

The inductance (L) of a coil wire (e.g solenoid) is given by;

L = μ₀N²A / l                 --------------(i)

Where;

l = the length of the solenoid

A = cross-sectional area of the solenoid

N= number of turns of the solenoid

μ₀ = permeability of free space = 4π x 10⁻⁷ N/A²

<em>From the question;</em>

N = 183 turns

l = 2.09cm = 0.0209m

diameter, d = 9.49mm = 0.00949m

<em>But;</em>

A = π d² / 4                     [Take π = 3.142 and substitute d = 0.00949m]

A = 3.142 x 0.00949² / 4

A = 7.1 x 10⁻⁵m²

<em>Substitute these values into equation (i) as follows;</em>

L = 4π x 10⁻⁷ x 183² x 7.1 x 10⁻⁵ / 0.0209           [Take π = 3.142]

L = 4(3.142) x 10⁻⁷ x 183² x 7.1 x 10⁻⁵ / 0.0209

L = 143 x 10⁻⁶ H

L = 143 μH

Therefore the inductance in microhenrys of the Tarik's solenoid is 143

6 0
3 years ago
Compared to the cells in a healthy body, Elisa’s cells are getting far fewer ____________________ molecules.
Elenna [48]

Answer:

glucose

Explanation:

7 0
3 years ago
Can you answer any of these?
givi [52]
#39. rain, snow, sleet and hail.
3 0
3 years ago
Read 2 more answers
A delivery man is told to go 60 miles per hour north to make his delivery on time. These instructions grab the delivery man's( 2
timama [110]

Answer:

The answer is B, velocity.

Explanation:

Just took the quiz. Hope this helps! Please count as braniliest.

4 0
3 years ago
Read 2 more answers
Question: Self-test 3.12 Calculate the change in G for ice at -10°C, with density 917 kg mº, when the pressure is increased from
Akimi4 [234]

The change in the Gibb's free energy per mole (G) is 1.96 J.

The given parameters:

  • Density of the ice, ρ = 917 kg/m³
  • Initial pressure, P₁ = 1.0 bar
  • Final pressure, P₂ = 2.0 bar
  • Temperature, T = - 10 C
  • Mass of water = 18 g

The change in the Gibb's free energy per mole (G) is calculated as follows;

\Delta G = V(P_2-P_1) \\\\

where;

V is the volume of the ice

Density = \frac{Mass}{Volume} \\\\Volume = \frac{Mass}{Density} \\\\Volume = \frac{18 \times 10^{-3} \ kg}{917 \ m^3} \\\\Volume = 1.96 \times 10^{-5} \ m^3\\\\Volume = 1.96 \times 10^{-5} \ m^3 \times \frac{1000 \ L}{m^3} \\\\Volume = 0.0196 \ L

Change in pressure;

P_2 - P_1 = 2.0 \ bar \ - \ 1.0 \ bar = 1.0 \ bar = 0.987 \ atm

The change in the Gibb's free energy per mole (G);

\Delta G= V(P_2-P_1)\\\\\Delta G = 0.0196\ L \times 0.987\ atm \\\\\Delta G = 0.0193 \ L.atm\\\\1 \ L.atm = 101.325 \ J\\\\\Delta G =  0.0193 \ L.atm \times \frac{101.325 \ J}{1 \ L.atm} \\\\\Delta G = 1.96 \ J

Thus, the change in the Gibb's free energy per mole (G) is 1.96 J.

Learn more about Gibb's free energy here: brainly.com/question/10012881

3 0
2 years ago
Other questions:
  • A small rectangular block of metal must be a magnet is it
    6·1 answer
  • What is transmitted by all waves
    6·2 answers
  • A 72 kg skydiver is descending on a parachute. His speed is still increasing at 1.2 m/s2. What are the magnitude and direction o
    15·1 answer
  • It is 5.00 km from your home to the physics lab. As part of your physical fitness program, you could run that distance at 10.0 k
    12·1 answer
  • The wheel of a car has a radius of 0.413 m. If the wheel rotates at 456 revolutions per minute, what is the speed (in m/s) at wh
    11·2 answers
  • Which statement is true?
    15·1 answer
  • Not in book
    14·1 answer
  • A 1000 kg rocket ship is traveling at 40 m/s. If the velocity changes to 70
    11·1 answer
  • The 60.0 kg skier shown below is skiing down a 35.0 degree incline where the magnitude of the friction force is 38.5N
    5·1 answer
  • <img src="https://tex.z-dn.net/?f=%5Chuge%5Cbold%7B%5Cpurple%7B%5Cbold%7B%E2%9A%A1Gravitational%20Constant%3F%E2%9A%A1%7D%7D%7D%
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!