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Neko [114]
3 years ago
15

Explain how characteristic and traits are related​

Physics
1 answer:
jok3333 [9.3K]3 years ago
4 0
Traits are basically your phenotype. They include things like hair color, height, and eye color. Alleles are versions of genes. ... This is a pretty basic idea of how traits and alleles are related.
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Explain, using your own example why you must always give a unit when reporting a measurement.
Ludmilka [50]
If you don't give unit with your magnitude (number) then, anyone can't figure it what you are talking about!
Suppose, you said, the weight of an iron bar is 10.
What does that mean? We can't even figure out how heavier is it. 

Now, If you tell that the weight of a person is 10 Newton, then it makes sense 'cause 10 N has specific value. When you wrote 10 then, it could be newton, dyne or any other derived unit.

Hope this helps!
5 0
3 years ago
What is the name given to the force exerted by the first object on a second object
Andre45 [30]
Soppose the 1 object is A and 2 is B then the force exerted by A on B is FAB and the force exerted on body B on A is -FAB.
6 0
3 years ago
If an object is not accelerating, then one knows for sure that it is_____.​
Sauron [17]
The object is maintaining a constant velocity
6 0
3 years ago
Marco is conducting an experiment. He knows the wave that he is working with has a wavelength of 32.4 cm. If he measures the fre
sergeinik [125]
We know, Speed = Wavelength * Frequency 
Speed = 32.4 * 3 
Speed = 97.2 m/s

So, option D is your correct answer.

Hope it helped.
4 0
3 years ago
Read 2 more answers
An LED operation at 850 nm center wavelength has a spectral width of 45 nm. What is the pulse spreading in ns/km
Papessa [141]

Answer:

\mathbf{\dfrac{\sigma_{mat}}{L} = 3.6 \ ns/ km}

Explanation:

From the given information, the LED is operating with a given wavelength of 850 nm or 0.85 μm.

Hence, the material dispersion is \dfrac {d \tau _{mat}}{d \lambda } \simeq (80 \ ps / (nm.km) \ )

Now, using the pulse spread formula:

\dfrac{\sigma_{mat}}{L} = \dfrac{d \tau _{mat} }{d \lambda} \sigma \lambda

\dfrac{\sigma_{mat}}{L} = (80 \ ps/ ( m.km) \ )  \times (45 \ nm)

Thus, the pulse spreading as a result of  material dispersion is:\mathbf{\dfrac{\sigma_{mat}}{L} = 3.6 \ ns/ km}

3 0
3 years ago
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