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sammy [17]
2 years ago
8

How many different combinations of chromatids are possible during the early phases of anaphase in meiosis II

Biology
1 answer:
Ket [755]2 years ago
4 0

Answer:

Explanation:) In mitosis, two genetically identical daughter cells are produced. Thus, the only possible combination of chromosomes is C1/C2/M1/M2/S1/S2 since all genetic material is inherited. b) The first meiotic division serves to split homologous pairs into two different cells, which are now haploid. There are 8 possible combinations of chromosomes (2 chromosomes for each homologous pair). For instance, a cell at this stage could inherit C1/M1/S1, or C2/M1/S1, or C1/M2/S1, etc. c) The same 8 combinations as above. The second meiotic division splits double-stranded chromosomes of each of these haploid cells into two daughter cells each so that only single-stranded chromosomes remain. Since no crossing over...

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0.44  the frequency of the homozygous individuals in this population.

What is Hardy-Weinberg principle ?

The Hardy-Weinberg equilibrium is a principle stating that the genetic variation in a population will remain constant from one generation to the next in the absence of disturbing factors.

From the Hardy Weinberg Law of Population and Genetics,

We have

x²+2xy+y²=1 and

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x = frequency of the dominant allele in the population

y = frequency of the recessive allele in the population

x2 = percentage of homozygous dominant individuals

y2 = percentage of homozygous recessive individuals

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Given 2xy = 0.56

from here, y=0.28/x, (the frequency of the recessive allele ) can be obtained

we need to find 'x'

recall, x+y=1, x=1-y

substituting this gives us

y=0.28/(1-y), which becomes,

y(1-y)=0.28

y²- y + 0.28 (quadratic equation)

Solving this to find 'y' gives two imaginary values of y = 0.44 but ,

There is no imaginary solution  .

Learn more about Hardy Weinberg Law of Population

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