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Setler79 [48]
2 years ago
12

You have $50 in your savings account and plan to deposit $10 each week. Your friend has $25 in her savings account and plans to

also deposit $10 each week.
A. Write a system of linear equations that represents this situation.

B. Will your friend's account ever have the same amount of money as your account? Explain.
Mathematics
2 answers:
Mariulka [41]2 years ago
7 0

Answer: 50+10x

Answer: 25+10x

Answer: No. 50+10x=25+10x. In simplified form, it is 0 =25 which is undefined (no solution).

Alisiya [41]2 years ago
6 0

For part B it's no because if you already have 50 dollars and she has 25, then you already have more money than your friend. Hope this helps

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What is the diameter of the circle?
Hatshy [7]
Hello!

The circumference is the diameter multiplied by pi. To find the diameter we will divide the circumference by pi (3.14).

1,133.54/3.14=361

361 is the diameter of the circle.

I hope this helps!
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6. Two observers, 7220 feet apart, observe a balloonist flying overhead between them. Their measures of the
MaRussiya [10]

Answer:

The ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

Step-by-step explanation:

Let's call:

h the height of the ballonist above the ground,

a the distance between the two observers,

a_1 the horizontal distance between the first observer and the ballonist

a_2 the horizontal distance between the second observer and the ballonist

\alpha _1 and \alpha _2 the angles of elevation meassured by each observer

S the area of the triangle formed with the observers and the ballonist

So, the area of a triangle is the length of its base times its height.

S=a*h (equation 1)

but we can divide the triangle in two right triangles using the height line. So the total area will be equal to the addition of each individual area.

S=S_1+S_2 (equation 2)

S_1=a_1*h

But we can write S_1 in terms of \alpha _1, like this:

\tan(\alpha _1)=\frac{h}{a_1} \\a_1=\frac{h}{\tan(\alpha _1)} \\S_1=\frac{h^{2} }{\tan(\alpha _1)}

And for S_2 will be the same:

S_2=\frac{h^{2} }{\tan(\alpha _2)}

Replacing in the equation 2:

S=\frac{h^{2} }{\tan(\alpha _1)}+\frac{h^{2} }{\tan(\alpha _2)}\\S=h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})

And replacing in the equation 1:

h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})=a*h\\h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}

So, we can replace all the known data in the last equation:

h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}\\h=\frac{7220 ft}{(\frac{1 }{\tan(35.6)}+\frac{1}{\tan(58.2)})}\\h=3579,91 ft

Then, the ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

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Answer:

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