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Eduardwww [97]
3 years ago
13

Explain how to write and evaluate the algebraic expression 13 less than the quotient of forty and a number; evaluate when n=2

Mathematics
2 answers:
madam [21]3 years ago
7 0

Answer:So you would start with 40/n because quotient means division and then it would be (40/n) - 13  (40 divided by n then minus 13) because the answer is thirteen less than the quotient of those numbers. since it wants you to evaluate for n=2 you would do 40/2 which is 20 then subtract 13 which is 7.

So write the expression as (40/n) -13 and when you evaluate just stick the 2 where the n is for (40/2) - 13

                               20 - 13

                                  = 7

Step-by-step explanation: HOPE THAT THIS WILL HELP YOU ❤️

g100num [7]3 years ago
3 0

Answer:

Here's an answer I used <3

Explanation:

You would then get to 40/n because quotient means division, then 40/n-13 because the outcome is 13 below the quotient. You can divide 40 by 20 to get 20, then 13 to get 7 because it asks you to test n=2.

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This is a system of equations  w/ 3 unknowns and 3 equations so we can solve this. :)

subtract Eq 2 from Eq 3

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Eq 1a) Gk + Hs +8 =33    simplify

Eq 1b) Gk + Hs = 25

Eq 3a) 2Gk +Hs +2(8) = 64  simplify

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Question 1  )  Gk = 23  Hs = 2 Lt = 8

solve new systems, same as above but  with the new prices

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Eq 2r) 2Gk + Hs + 0Lt = 29

Eq 3r) 2Gk + Hs + 2Lt =35

subtracting 2r from 3r we get 2Lt = 6   then Lt =3  for the new price

plug that into 1r and 3r

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Question 3)  wants 2 Hs and 2 Lt

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