Step-by-step explanation: To solve these, call each given zero = z. The function is when given a zero that is an integer (x-z1)(x-z2)(x-z3)... so on until all zeroes are used. This works for fractions also. But when you have irrationals, you will have to make sure each irrational solutions conjugate is there. So if a given zero is 2-sqrt3, then always 2+sqrt3 will also be a 0. Likewise, if given -4-sqrt7, then -4+sqrt7 will also always be a zero. Use this logic to solve them very quickly! I hope this helps!
