Using the z-distribution, as we are working with a proportion, it is found that the 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, the parameters are:

The lower limit of this interval is:

The upper limit of this interval is:

The 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.
More can be learned about the z-distribution at brainly.com/question/25890103
Answer:
8.9m/s
Step-by-step explanation:
Time= 28s
Displacement= 250m
Velocity=?
Velocity (v) = displacement (d)/ Time (t)
V= 250/28
V=8.9m/s
OR YOU CAN APPROXIMATE IT
V=8.928
YOU CAN APPROXIMATE IT TO
V=8.93m/s
Answer:

Step-by-step explanation:

1/2 of 22:
1/2 · 22 = 22/2 = 11
2/3 of 16
2/3 · 16 = 32/3 = 10 2/3
Answer:

Step-by-step explanation:
Given
per person
Required
Represent as an equation
For 1 person, the admission fee is 2
For p people, the admission fee will be 2p.
Hence:
