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Elenna [48]
3 years ago
5

The base of a rectangular prism has an area of 26.25, and the height of the prism is 4.5. What is the volume? Round to the neare

st hundredths.

Mathematics
2 answers:
kramer3 years ago
4 0

The right answer is 118.

Look at the attached picture

Hope it will help you....

Good luck on your assignment.

son4ous [18]3 years ago
3 0

Answer:

v = 118.25

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em>

<em>brainliest</em><em> </em><em>appreciated</em>

<em>good</em><em> </em><em>luck</em><em>!</em><em> </em><em>have</em><em> </em><em>a</em><em> </em><em>nice</em><em> </em><em>day</em><em>!</em>

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If you want to turn a fraction to a decimal, you have to divide the numerator by the denominator in order to get a decimal number. If the fraction is a mixed number, you would do the same but make sure that the whole number is in front of the decimal.
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Difference of squares<br> 9x^2-4
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(3x+2)(3x-2)

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(3x+4)(x-2)<br> A.3x^2-2x-8<br> B.x-8<br> C.3x-2x-8<br> D.3x^2+2x+8
vlada-n [284]

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A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang
laiz [17]

<u>Answer-</u>

a. Probability that  three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

<u>Solution-</u>

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

\binom{19}{3} = \frac{19!}{3!16!} = 969

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

\binom{33}{6} = \frac{33!}{6!27!} =1107568

So total number of selection = (969)×(1107568) = 1073233392

Drawing 9 candies out of 52 candies,

\binom{52}{9} = \frac{52!}{9!43!} = 3679075400

∴P(3 white candies) = \frac{1073233392}{3679075400} =0.29



Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}

=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})

=(969)(45)(7)(5)(15)=22892625

Total number of selection = 3 whites + 2 are tans + 1 is pink + 1 is yellow + 2 greens = 9 candies out of 52 candies is,

\binom{52}{9}=\frac{52!}{9!43!} =3679075400

∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =

\frac{22892625}{3679075400} = 0.006


6 0
3 years ago
Log2+ log8=2<br><br>how do I do it?​
soldi70 [24.7K]

Answer:

Step-by-step explanation:

log(2)+log(8) = 2

1.20412≠2

False

8 0
3 years ago
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