Answer:
The length of AE is 20 units.
Step-by-step explanation:
Given two segments AD and BC intersect at point E to form two triangles ABE and DCE. Side AB is parallel to side DC. A E is labeled 2x+10. ED is labeled x+3. AB is 10 units long and DC is 4 units long.
we have to find the length of AE
AB||CD ⇒ ∠EAB=∠EDC and ∠EBA=∠ECD
In ΔABE and ΔDCE
∠EAB=∠EDC (∵Alternate angles)
∠EBA=∠ECD (∵Alternate angles)
By AA similarity, ΔABE ≈ ΔDCE
therefore, 
⇒ 
⇒ 
⇒ 
Hence, AE=2x+10=2(5)+10=20 units
The length of AE is 20 units.
Answer:
a) cblo
2)$3.44
Step-by-step explanation:
4 cans and 3 loaves=11.67
8 cans and 1 loaf= 12.89.
Set up equation:
x=cans
y=loaves
This is the answer for question A.
Multiply eq1 by 2:
Subtract eq3 by eq2:
Substitute:
One can of soup and one loaf of bread=
So:
Hope this helps :D Please hit the crown if u can !!
Answer:
Area of triangle is 9.88 units^2
Step-by-step explanation:
We need to find the area of triangle
Given E(5,1), F(0,4), D(0,8)
We will use formula:
We need to find the lengths of side DE, EF and FD
Length of side DE = a = 
Length of side DE = a = 
Length of side EF = b =
Length of side EF = b = 
Length of side FD = c =
Length of side FD = c = 
so, a= 8.60, b= 5.8 and c = 4
s = a+b+c/2
s= 8.6+5.8+4/2
s= 9.2
Area of triangle=
So, area of triangle is 9.88 units^2
Set each factor equal to zero and solve.
x + 6 = 0 x - 3 = 0
x = - 6 x = 3
