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Feliz [49]
3 years ago
5

PLEASE HELP!!! Write an equation for the following scenario.

Mathematics
1 answer:
alexandr402 [8]3 years ago
7 0

Answer:2n + 8 = n-3

Step-by-step explanation:

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Tom has been playing on the school bowling team. In his first year as a freshman, his bowling average was 180. He had been bowli
Advocard [28]

Answer:

0.000025

Step-by-step explanation:

the difference between225-180=45

so the percentage= 45×100/100

=0.45%

as the instruction say=0.45%/180

=0.0045/180

=45/1800000

=0.000025

3 0
3 years ago
Show me how to solve 6j-3 for j=4
aleksklad [387]

Answer:

21

Step-by-step explanation:

plug in 4 where you have the j

6(4)-3=

24-3=

21

6 0
3 years ago
Piper deposited $734.62 in a savings account that earns 2.6% simple interest. What is Piper’s account balance after seven years?
r-ruslan [8.4K]
That would be $868.32 okay :)
5 0
3 years ago
The factor (x + 2) occurs in the numerator and denominator. There will be a hole at x = 2.
navik [9.2K]

Answer:

false

Step-by-step explanation:

it suppose to be -2 if you equate it to Zero

6 0
3 years ago
Santos is a lifeguard and spots a drowning child 50 meters along the shore and 60 meters from the shore to the child. Santos run
Amanda [17]

Answer:

Santos should run approximately 36.145 meters along the shore

Step-by-step explanation:

The given parameters are;

The distance along the shore of the child = 50 meters

The distance from the shore of the child = 60 meters

The rate at which Santos can run = 4 m/s

The rate he can swim = 0.9 m/s

Let 'x' represent the distance he runs along the shore

We have;

The time he spends running on the shore, t₁ = x/4

The time he spends swimming, t₂ = (√(60² + (50 - x)²)/0.9

The total time, T = t₁ + t₂ = x/4 + (√(60² + (50 - x)²)/0.9

To find the maximum, we have;

dT/dx = 0 = d(x/4 + (√(60² + (50 - x)²)/0.9)/dx = 1/4 - (50 - x)/(0.9·(√(60² + (50 - x)²) = 0

1/4 - (50 - x)/(0.9·(√(60² + (50 - x)²) = 0

Simplifying using a graphing calculator gives;

\dfrac{x - 2000}{9} = \sqrt{x^2-100\cdot x+6,100}

1519·x² - 151900·x + 3505900 = 0

x = (151900 ± √((-151900)² - 4×1519×3505900))/(2 × 1519)

x ≈ 63.86 m or x ≈ 36.145 m

We note that the distance from a point x = 63.83 meters and 36.145 meters from where Santos spots the girl to the location of the girl are the same

Therefore, Santos should run approximately 36.145 meters along the shore before jumping into to the water in order to save the child

7 0
3 years ago
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